Question

Q\ Suppose we have dice; the dice have six outcomes find the probability of the
following: -
a) What’s the probability of rolling a 4?
b) What’s the probability of rolling an odd number?
c) What’s the probability of rolling less than 6?
d) What’s the probability of rolling a 1 and 3?
e) What’s the probability of rolling a 0?
f) The probability of event a or c?
g) What’s the probability of rolling not event b?

Answer 1

Note: Final answers are highliighted in colour

a)Probability of rolling a 4=1/6

b)What’s the probability of rolling an odd number

Number of ddd numbers on a dice n(E)= 3 (1,3,5)

Total possible outcomes n(Total)= 6

Therefore, The probability of rolling an odd number = n(E)/n(Total)= 3/6= 0.5

c)

Number of dice outcomes less than 6 n(E)= 5(1,2,3,4,5)

Total possible outcomes n(Total)= 6

Therefore, the probability of rolling less than 6= n(E)/n(Total)= 5/6= 0.8333

d)

Number of allowed outcomes =n(E)= 2(1 and 3)

Total possible outcomes= n(Total)= 6

Therefore, the probability of rolling a 1 or a 3= 2/6= 0.333

e)

Number of allowed outcomes =n(E)= 1(0)

Total possible outcomes= n(Total)= 6

Therefore, the probability of rolling a 0= n(E)/n(Total)= 1/6=0.167

f)

Proabability of rolling a 4 or rolling less than 6= p(rolling less than 6)

Because rolling less than 6 already contains the outcome of rolling a 4.

Therefore, probability of event a or c= p(c)= 0.8333

g)

Probability of rolling not event b= 1-p(b)= 1-0.5= 0.5