In: Finance
A stock initially selling at $100 could increase by 10% with probability of 60% or decrease by 10% with probability of 40% every six months. Suppose that the continuous interest rate is 5% per six-month. A call option on the stock specifies an exercise price of $100 and a time to expiration of one year, what is its price using binomial pricing method? A) 6.78 B) 4.75 C)6.84 D. None of the above
Discrete interest rate = e^5% -1 = 5.13%
S0 = | Stock price today | = | 100 | |
r= | risk free interest rate | = | 5.127% | |
u= | up factor | = | 1.1 | |
d= | Down factor | = | 0.9 | |
X = | Exercise price | = | 100 | |
We first compute the possible values of the stock at each node in the binomial tree: | ||||
t=1 | ||||
S+ = | = 100*1.1 | = | 110 | |
S- = | = 100*0.9 | = | 90 | |
t = 2 = T | ||||
S++ = | = 100*1.1*1.1 | = | 121 | |
S+ - = | = 100*1.1*0.9 | = | 99 | |
S- - = | = 100*0.9*0.9 | = | 81 | |
Intrinsic value of the call option at expiration | ||||
c++ = | = Max(0, S++ - X) | |||
= Max(0, 121 - 100) | = | 21 | ||
c+ - = | = Max(0, S+ - - X) | |||
= Max(0, 99 - 100) | = | 0 | ||
c- - = | = Max(0, S- - - X) | |||
= Max(0, 81 - 100) | = | 0 | ||
∏= | = | |||
∏= | Probability of up | = | 0.6000 | |
1- ∏= | = | 0.4000 | ||
Compute the value of call option at each node for t=1 | ||||
c+ = | Call price t=1 | = | [∏c++ + (1-∏)c+ - ]/ (1+r) | |
c+= | [0.6*21 + 0.4*0] /[1+0.0512710963760241 ] | = | 11.99 | |
c- = | Call price t=1 | = | [∏c+ - + (1-∏)c- - ]/ (1+r) | |
[0.6*0 + 0.4*0] /[1+0.0512710963760241 ] | = | - | ||
Finally, value of call option | ||||
c = | Call price t=0 | = | [∏c+ + (1-∏)c - ]/ (1+r) | |
c = | Call price today | |||
[0.6*11.99 + 0.4*0] /[1+0.0512710963760241 ] | = | 6.84 |
Answer is 6.84
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