In: Chemistry
1. How many GRAMS of
nitrogen are present in 3.97
moles of dinitrogen tetrafluoride ? grams.
2. How many MOLES of
fluorine are present in 2.72
grams of dinitrogen tetrafluoride ? moles.
1) mass of 3.97 moles of dinitrogen tetrafluoride = 3.97 * 104 = 412.88 grams.
104 grams of dinitrogen tetrafluoride contains = 28 grams of Nitrogen then
412.88 grams of dinitrogen tetrafluoride contains = 28 X 412.88 /104
= 111.16 grams Nitrogen.
2) 104 grams of dinitrogen tetrafluoride contains = 76 grams of Fluorine
2.72 grams of dinitrogen tetrafluoride contains = 1.988 grams of Fluorine
1.988 grams of Fluorine moles = 1.988/19 = 0.105 moles of Fluorine