1. How many GRAMS of nitrogen are present in 3.97 moles of dinitrogen tetrafluoride ? grams....

1. How many GRAMS of nitrogen are present in 3.97 moles of dinitrogen tetrafluoride ? grams.

2. How many MOLES of fluorine are present in 2.72 grams of dinitrogen tetrafluoride ? moles.

Solutions

Expert Solution

1) mass of 3.97 moles of dinitrogen tetrafluoride = 3.97 * 104 = 412.88 grams.

104 grams of dinitrogen tetrafluoride contains = 28 grams of Nitrogen then

412.88 grams of dinitrogen tetrafluoride contains = 28 X 412.88 /104

= 111.16 grams Nitrogen.

2) 104 grams of dinitrogen tetrafluoride contains = 76 grams of Fluorine

2.72 grams of dinitrogen tetrafluoride contains = 1.988 grams of Fluorine

1.988 grams of Fluorine moles = 1.988/19 = 0.105 moles of Fluorine

queen_honey_blossom answered 1 year ago

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