What is the pH of a solution made by diluting 0.064 moles of CH3COOH (Ka =...

What is the pH of a solution made by diluting 0.064 moles of CH3COOH (Ka = 1.8 x 10-5) in 147 mL of water?

Expert Solution

Molarity of CH3COOH = (number of moles of solution)/(volume of solution in L)

=> 0.064/(147/1000) = 0.435M

Initial 0.435M 0 0

Final (0.435 - x) x x

assuming (0.435-x) is approximately equal to 0.435

queen_honey_blossom answered 2 years ago

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