Question

Case study: TBS Shipping

1. Assuming the MV Hamburg Pearl has a DWT of 44,500 MT, an empty weight of 6,500 MT, and a crew, stores, and fuel weight of 1,000 MT, estimate how much of the following will fit into the cargo holds, without exceeding the ship's volume or weight limits:

Sunflower seeds: Blank 1 MT
Cobalt: Blank 2 MT
Peanuts (unshelled): Blank 3 MT

To answer this, you will need to look up standard values for stowage factors and calculate the answers. If you find the stowage factor is a range, use a value in the center of that range.

Answer 1

Answer :

For sunflower seeds :

DWT = 44500 MT

Net deadweight capacity = (44500 - 6500 - 1000) = 37000 MT

Sunflower seeds : Blank 1 MT

So, sunflower cubic capacity = 37000 m³

As per handbook for cargo

Stowage factor = 2.19 - 2.50 m³ / t (bulk)

So, taking stowage factor = 2.345 m³ /t

So, ship can lift

(37000 / 2.345) = 15764.80 MT

Ship can take 15764.80 MT of sunflower seeds

For cobalt :

Cobalt = Blank 2 MT

As per handbook for cargo

Stowage factor = 0.7 to 0.8 m³ / t

So, taking stowage factor

= 0.75 m³ / t

So, cobalt cubic

Capacity = (37000/2) = 18500 MT

Ship can lift (18500 / 0.75) = 24666.67 MT

Ship can take 24666.67 MT of cobalt

For Peanut :

Peanut = Blank 3 MT

As per handbook for cargo

Stowage factor = 2.35 to 2.44 m³ / t

So, taking stowage factor = 2.395 m³ / t

So, Peanut cubic

capacity = (37000/3) = 12333.33 MT

Ship can lift = (12333.33/3) = 4111.11 MT

Ship can take 4111.11 MT of Peanut.