Question

In: Chemistry

1) 1.95 moles of HBr in 250.0 mL flask is consumed in 1.00 minutes in the...

1) 1.95 moles of HBr in 250.0 mL flask is consumed in 1.00 minutes in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) at 150°C.   The rate of reaction is __________ M∙s-1.

3.85

0.0650

0.0169

0.260

0.0860

2)The reaction A → C is found to be zero order. Which of the following will give a linear plot?

(A) vs. time

ln(A) vs. time

1/(A) vs. time

None of these will be linear.

3)Which of the following is not a colligative property?

depression of solvent vapor pressure upon addition of a solute to a solvent

elevation of the boiling point of a solution upon addition of a solute to a solvent

depression of the freezing point of a solution upon addition of a solute to a solvent

an increase in the osmotic pressure of a solution upon the addition of more solute

the increase of reaction rates with increase in temperature

4)

Yeast and sugar are added to champagne to give the sparkle of carbonation. Under what conditions is carbon dioxide gas most soluble?

low temperature, high pressure

low temperature, low pressure

high temperature, low pressure

high temperature, high pressure

none of these

5)

In general, the solubility of ________ in water decreases as temperature increases.

liquids

solids

gases

none of these

6) In a solution, the solvent is:

always water

the substance in the greatest amount

the substance that is dissolved

always a gas

Solutions

Expert Solution

Q1 Solution :-

Balanced reaction equation is

2HBr ------ > H2   + Br2

1 min = 60 sec

Rate = ½ delta [HBr]/delta T

Molarity of the HBr = 1.95 mol / 0.250 L = 7.8 M

Rate = ½ [7.8M] / 60 sec

Rate = 0.065 Ms-1

Q2 solution

For the zero order reaction a plot of concentration verses time gives the linear plot therefore the correct answer is the

(A).Vs. time that is the first option.

Q3 solution

Elevation in boiling point. Depression freezing point, depression of vapor pressure and osmotic pressure are the colligative properties which depends on the molal concentration of the solution

Therefore the statement provided in the last option that is

Increase in the reaction rate with increase in the temperature is not the colligative property.

Q4 solution

When the temperature is low and pressure is high then gas is more soluble in the liquid therefore the correct answer is the first option

That is low temperature, high pressure

Q5 solution :-

The solubility of the gas decreases with increase in temperature.

Therefore the correct answer is option 3 that is gases

Q6 solution :-

Solvent is the liquid portion of the solution which dissolves the solute therefore the amount of the solvent is higher than the solute

Therefore the correct answer is the option 2 that is

The substance in the greatest amount.


Related Solutions

To a 250.0 mL volumetric flask are added 1.00 mL volumes of three solutions: 0.0100 M...
To a 250.0 mL volumetric flask are added 1.00 mL volumes of three solutions: 0.0100 M AgNO3, 0.150M NaBr, and 0.100 M NaCN. The mixture is diluted with deionized water to the mark and shaken vigorously. The Ksp of AgBr is 5.40×10–13 and the Kf of Ag(CN)2– is 1.00×1021. What mass of AgBr would precipitate from this mixture? Do not simply write "0" as some precipitate will form.
to a 100.0 mL volumetric flask are added 1.00 mL volumes of three solutions: .0100 M...
to a 100.0 mL volumetric flask are added 1.00 mL volumes of three solutions: .0100 M AgNO3, .205 M NaBr, and .100 M NaCN. The mixture is diluted with deionized water to the mark and shaken vigerously. What mass of AgBr would precipitate from this mixture? Hint: The Ksp of AgBr is 5.4 x 10-13 and the Kf of Ag(CN)2- is 1.0 x 10^21
Starting with 0.25 moles of sodium phosphate (Na3PO4) in 1.00 L volumetric flask, determine the pH...
Starting with 0.25 moles of sodium phosphate (Na3PO4) in 1.00 L volumetric flask, determine the pH of the resulting solution upon addition of the amounts of hydrochloric acid shown in the table below. Each of the solutions were diluted to a final volume of 1.00 L. Moles of HCl pH 0.00 0.15 0.25 0.75 1.00
Property Flask 1 Flask 2 Flask 3 Flask 4 Contents 100 ml water 100 ml water...
Property Flask 1 Flask 2 Flask 3 Flask 4 Contents 100 ml water 100 ml water 74ml acetic acid,1.1g sodium acetate, 26ml water 74ml acetic acid, 1.1g sodium acetate,26 ml water Initial pH 7.00 7.00 5.01 5.01 pH after adding strong acid(HCL) 2.32 4.97 pH after adding strong base(NAOH) 11.68 5.06 1. Compare what happen to the pH of flask 1 to what happened to the pH of flask 3 when HCl was added. 2. Which substance, water or the...
Consider the titration of 100.0 mL of 0.100 M NaOH with 1.00 M HBr. Find the...
Consider the titration of 100.0 mL of 0.100 M NaOH with 1.00 M HBr. Find the pH at the following volumes of acid added. Va = 0 mL Va = 1.0 mL Va = 5.0 mL Va = 9.0 mL Va = 9.9 mL Va = 10.0 mL Va = 10.1 mL Va = 12.0 mL Make a graph of pH versus Va = 0, 1.0, 5.0, 9.0, 9.9, 10.0, 10.1, and 12.0 mL.
To a 150.0mL volumetric flask are added 1.00 mL volumes of three solutions: 0.0100 M AgNO3,...
To a 150.0mL volumetric flask are added 1.00 mL volumes of three solutions: 0.0100 M AgNO3, 0.225 M NaBr, and 0.100 M NaCN. The mixture is diluted with deionized water to the mark and shaken vigorously. What mass of AgBr would precipitate from this mixture? (Hint: The Ksp of AgBr is 5.4x10-13 and the Kf of Ag(CN)2- is 1.0x1021)
To a 100.0mL volumetric flask are added 1.00 mL volumes of three solutions: 0.0100 M AgNO3,...
To a 100.0mL volumetric flask are added 1.00 mL volumes of three solutions: 0.0100 M AgNO3, 0.190 M NaBr, and 0.100 M NaCN. The mixture is diluted with deionized water to the mark and shaken vigorously. What mass of AgBr would precipitate from this mixture? (Hint: The Ksp of AgBr is 5.4x10-13 and the Kf of Ag(CN)2- is 1.0x1021)
1. You make a solution of 0.464 moles HClO2 and 0.464 moles ClO2- dissolved in 1.00...
1. You make a solution of 0.464 moles HClO2 and 0.464 moles ClO2- dissolved in 1.00 L. What is the minimum number of moles of KOH would need to be added in order to 'overwhelm' this buffer? 2. You make a solution of 0.316 moles HClO2 and 0.464 moles ClO2- dissolved in 1.00 L. What is the minimum number of moles of KOH would need to be added in order to 'overwhelm' this buffer?
A 1.100−L flask at 25∘C and 1.00 atm pressure contains CO2(g) in contact with 100.0 mL...
A 1.100−L flask at 25∘C and 1.00 atm pressure contains CO2(g) in contact with 100.0 mL of a saturated aqueous solution in which [CO2(aq)] = 3.29×10−2 M. a) What is the value of Kc at 25∘C for the equilibrium CO2(g)⇌CO2(aq) Answer: Kc = 0.804 b) If 0.01400 M of radioactive 14CO2 is added to the flask, how many moles of the 14CO2 will be found in the gas phase and in the aqueous solution when equilibrium is reestablished? [Hint: The radioactive 14CO2 distributes itself between the two phases in exactly the same...
Reaction: 1 PbBr2 + 2 HCl --> 2 HBr + 1 PbCl2 How many moles of...
Reaction: 1 PbBr2 + 2 HCl --> 2 HBr + 1 PbCl2 How many moles of PbBr2 are needed to react with 2 moles of HCl? Blank 2 mole How many moles of PbCl2 are produced from 1.23 x 10^28 moles of HCl? The answer is 6.15x10^__ Blank 3 What is the molar mass of PbCl2? Blank 4g/mole How many grams of PbCl2 are produced from 1.23x10^28 moles of HCl? The answer is 1.71x10^__ Blank 5   
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT