In: Statistics and Probability
An adjunct instructor teaches the same statistics class at three different colleges. She wants to compare the average age of students in the three classes.
School 1 | 25 | 23 | 23 | 21 | 19 | 17 | 20 | 21 | 31 | 29 |
---|---|---|---|---|---|---|---|---|---|---|
School 2 | 26 | 21 | 23 | 24 | 19 | 22 | 19 | 24 | 28 | 31 |
School 3 | 24 | 23 | 22 | 22 | 20 | 19 | 22 | 23 | 30 | 28 |
(a)
Compute the grand mean.
(b)
Calculate the sum of squares treatment.
(c)
What is the sum of squares error?
(d)
What is the mean squares treatment?
(e)
What is the mean squares error? (Round your answer to four decimal places.)
(f)
Calculate the F statistic. (Round your answer to three decimal places.)
School 1 | School 2 | School 3 | |
25 | 26 | 24 | |
23 | 21 | 23 | |
23 | 23 | 22 | |
21 | 24 | 22 | |
19 | 19 | 20 | |
17 | 22 | 19 | |
20 | 19 | 22 | |
21 | 24 | 23 | |
31 | 28 | 30 | |
29 | 31 | 28 | |
Total(yi) | 229 | 237 | 233 |
Averages y̅i | 22.9 | 23.7 | 23.3 |
Treatment Effect | 22.9 - 23.3 = -0.4 | 23.7 - 23.3 = 0.4 | 23.3 - 23.3 = 0 |
Overall total = 699
Overall mean µ = 699 / 30 = 23.3
y̅i .. is overall mean
y̅i. is treatment mean
SST = ΣΣ(Yij - Y̅..)2
SS treatment = ΣΣ(Yij - y̅i.)2
SS error = Σ(y̅i. - Y̅..)2
Sum of Squares | Degree of freedom | Mean Square | F0 = MST / MSE | P value | |
Treatment | 3.2 | 2 | 1.6 | 0.1061 | 0.8997 |
Error | 407.1 | 27 | 15.0778 | ||
Total | 410.3 | 29 |
Part a)
Overall mean µ = 699 / 30 = 23.3
Part b)
SS treatment = ΣΣ(Yij - y̅i.)2 = 3.2
Part c)
SS error = Σ(y̅i. - Y̅..)2 = 407.1
Part d)
MS treatment = SS treatment / a-1 = 1.6
Part e)
MS error = SS error / N-a = 15.0778
Part f)
F0 = MST / MSE = 0.106