Question

Chi- squared Goodness of fit

7) An education council says that 22% of undergraduates do not work, 26 % work 1 to 20 hours per week, 18% work 21 to 34 hours per week, and 34% work 35 or more hours per week. You randomly select 120 college students and gather the results shown in the table below. At alpha = 0.01 can you reject the council`s claim.

Response
Did not work	29
Work 1 to 20 hours	26
Work 21 to 34 hours	25
Work 35 or more hours	40

a. State the null and alternative hypothesis
b. Give the p-value
c. Give a conclusion for the claim

Answer 1

ANSWER::

The p-value computed by using R-code is

F=c(29,26,25,40)

P=c(0.22,0.26,0.18,0.34)

chisq.test(F,p=P)

Chi-squared test for given probabilities

data: F

X-squared = 1.6736, df = 3, p-value = 0.6428

#p-value=0.6428>alpha=0.01 then we fail to reject the null hypothesis Ho

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