the product in a Coumarin synthesis lab is soluble in aqueous base. Why? 1.The base deprotonates...

the product in a Coumarin synthesis lab is soluble in aqueous base. Why?

1.The base deprotonates α- to the carbonyl to form an enolate ion.

2.The base deprotonates α- to the phenol to form a phenylate anion.

3.The base deprotonates the phenol hydroxyl to form a phenoxide anion.

4.The product is water soluble.

Expert Solution

Answer: 3.The base deprotonates the phenol hydroxyl to form a phenoxide anion.

Reason: I have attached Dry lab page below for your kind consideration and hope the same product you synthesized, if not no worries - the phenol hydroxyl group is deprotonated in all types of products formed from Coumarin.

queen_honey_blossom answered 1 week ago

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