Question

Please solve for the initial temperature of the ice. The procedure is provided for better understanding and data collected during procedure is provided below. Please use the initial equation and simplification provided. The initial equation (1) is further simplified in equation (2) to equation (3) to solve for the Initial Temperature of the Ice. Please follow the equations and explain your work in detail. Thank you very much!!

Procedure II:

Initial Temperature –

a. Prepare VERY cold ice. The specific heat of ice is cice = 0.500 cal/(g ˚C)

b. Place a known mass of Warm water in your calorimeter and measure its temperature.

c. Place the VERY cold ice in your calorimeter minimizing any heat loss to the environment as best you can.

d. While gently stirring the contents of the calorimeter, allow the water to reach a final equilibrium temperature. You can now measure and record the mass of, what was, VERY cold ice.

e. Use the principle of calorimetry to calculate the initial temperature of the sample.

The Latent Heat of Fusion for Ice = 79.7 cal/g.  

Water Mass = Mass w/ Water – Mass Empty. 626.6 g – 330.2 g = 296.4 g.  

Mass of Ice = Final Mass – Mass w/ Water. 662.0 g – 626.6 g = 35.4 g.

(mWcWΔTw) + (micecice ΔTice) + miceLf +  (micecw ΔTice+w) = 0

Tice=Tice final-Tice initial = 0 - Tice initial = - Tice initial

Tice+w=Tice+w final - Tice+w initial = Ticew final - 0 = Ticew final

Procedure 2
Mass Empty	Mass w/ Water	Water Mass	Final Mass	Mass of Ice	Initial Water Temp	Initial Ice Temp	Final Ice Temp	Initial Ice Water Temp	Temp Final
330.2 g	626.6 g	296.4 g	662.0 g	35.4 g	86.9 ℃	-230.75 ℃	0℃	0℃	69.0 ℃

Answer 1

According to calorimeter principle

Heat gain=Heat loss

Suppose the initial temperature of ice is Ti. LEt Q 1 is the energy gained by the ice to reach the temperature 0 0C from initial temperature and can be given as

In the second stage ice will start to melt then the energy gained by it is Q2

Now the ice converted to water so in this case the energy gained Q3 can be given as

Heat energy lost by the water Q_w is

Using Calorimetry principle

Initial temperature of ice is -2.35 degree centigrade