Question

Write a Python program that reads an integer and prints how many digits the number has, by checking whether the number is ≥10,≥100,≥1000, and so on (up to 1,000,000). Your program should also identify if a number is negative.

Answer 1

Python Program that print number of digit and identify if number is negative:

# Prompt for user input here input() function return string
# so we need to convert string to int first by using int() function.
number = int(input("Enter any number: "))

numOfDigit = 0  # Variable to hold number of digit

# first we need to check with higher number(Which is 1000000 in this case)
# then continue checking for lower values.
# Check if number is greater than 1000000
if number >= 1000000:
    numOfDigit = 7
# Check if number is greater than 100000
elif number >= 100000:
    numOfDigit = 6
# Check if number is greater than 10000
elif number >= 10000:
    numOfDigit = 5
# Check if number is greater than 1000
elif number >= 1000:
    numOfDigit = 4

# Check if number is greater than 100
elif number >= 100:
    numOfDigit = 3
# Check if number is greater than 10
elif number >= 10:
    numOfDigit = 1

#  check if number is negative that is less than 0
if number < 0:
    print(number, "is negative")

# if number is greater than 0 then print number of digit.
else:
    print("Number of digit: ", numOfDigit)

Sample Outputs :

Screenshot of Code :