Question

In: Statistics and Probability

A medical researcher wants to determine if an experimental drug to control the COVID 19 Virus...

A medical researcher wants to determine if an experimental drug to control the COVID 19 Virus has any effect on the motor skills scores of human subjects. She randomly assigns patients to 1 of 2 groups. Nine hundred subjects in group 1 (the experimental group) are given an oral dose of the drug prior to testing (mean = 9.78, standard deviation = 4.05); 1000 subjects in group 2 (control group) receive a placebo (mean = 15.10, standard deviation = 4.28). Test the null hypothesis (at 95% confidence) that there is no difference between the population means of the drug group & the placebo group. What do you conclude? Please show work. Thank you very much!

Solutions

Expert Solution

Sol:

since sample size is large we can use z distribution.

null hypothesis: Ho: μ1-μ2 = 0

Alternate hypothesis: Ha: μ1-μ2 ≠ 0

for 0.05 level with two tail test , critical z= 1.960

Decision rule : reject Ho if absolute value of test statistic |z|>1.96

Population 1 Population 2
x1            = 9.78 x2            = 15.10
n1           = 900 n2           = 1000
σ1           = 4.05 σ2           = 4.28

std error σx1-x2 = √(σ21/n1+σ22/n2)

=sqrt(4.05^2/900+4.28^2/1000)

σx1-x2 = 0.191

test stat z =(x1-x2-Δo)/σx1-x2    

=(9.78-15.10)/0.191

z = -27.83

since test statistic falls in rejection region we reject null hypothesis

we have sufficient evidence to conclude that there is  difference between the population means

of the drug group & the placebo group

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