Question

In: Statistics and Probability

A company is trying to choose between three types of cars for its fleet: national, Japanese...

A company is trying to choose between three types of cars for its fleet: national, Japanese or European. Five cars of each type are ordered and after traveling 10,000 miles with them, the cost per mile traveled (cents) of each car is calculated.

Nationals: 18.0, 17.6, 17.4, 19.1, 16.9
Japanese: 15.1, 16.6, 16.1, 15.3, 15.4
Europeans: 19.3, 17.4, 17.1, 18.6, 16.1

1) Make the hypothesis test (6 steps). In step 1, Ho and H1, write them in a text (don't write Ho:
2) Take the Tukey test. What type of car do you recommend?

Solutions

Expert Solution

A B C D
count, ni = 5 5 5
mean , x̅ i = 17.800 15.70 17.70
std. dev., si = 0.828 0.628 1.263
sample variances, si^2 = 0.685 0.395 1.595
total sum 89 78.5 88.5 256 (grand sum)
grand mean , x̅̅ = Σni*x̅i/Σni =   17.07
square of deviation of sample mean from grand mean,( x̅ - x̅̅)² 0.538 1.868 0.401
TOTAL
SS(between)= SSB = Σn( x̅ - x̅̅)² = 2.689 9.339 2.006 14.03333
SS(within ) = SSW = Σ(n-1)s² = 2.740 1.580 6.380 10.7000

no. of treatment , k =   3
df between = k-1 =    2
N = Σn =   15
df within = N-k =   12
  
mean square between groups , MSB = SSB/k-1 =    7.0167
  
mean square within groups , MSW = SSW/N-k =    0.8917
  
F-stat = MSB/MSW =    7.8692

anova table
SS df MS F p-value F-critical
Between: 14.03 2 7.02 7.87 0.0066 3.89
Within: 10.70 12 0.89
Total: 24.73 14
α = 0.05
conclusion : p-value<α , reject null hypothesis    

................

TUKEY:

Level of significance 0.05
no. of treatments,k 3
DF error =N-k= 12
MSE 0.892
q-statistic value(α,k,N-k) 3.7700
critical value = q*√(MSE/n)
confidence interval
population mean difference critical value lower limit upper limit result
µ1-µ2 2.10 1.59 0.51 3.69 means are different
µ1-µ3 0.10 1.59 -1.49 1.69 means are not different
µ2-µ3 -2.00 1.59 -3.59 -0.41 means are different

...............

JAPANESE CAR IS RECOMMENDED

..................

THANKS

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