Question

1. The reaction of soda ash (Na2CO3) with calcium sulfate in water is represented by the following chemical reaction: Na2CO3 + CaSO4 ......CaCO3 + Na2SO4. Assuming that this reaction is complete and that there is 153 mg/l of CaSO4 initially present, what is the mass of soda ash that must be added to 1 liter of the water to complete the reaction?

2. How many grams of CaO are required to be the chemical equivalent of 246 g of Mg(HCO3)2?

Answer 1

Answer 1.

The chemical reaction between soda ash and calcium sulfate reaction is 1: 1, this means that one mole of soda ash reacts with one mole of calcium sulfate

If a liter of solution have 153 mg of calcium sulfate, we will calculate how many moles (n) is that mass (MWCaSO4: 142,04g/mol):

To complete the reaction must be added to one liter solution the same number of moles of soda ash (PM_SODA=105,99g/mol):

mass of soda that must be added to 1 liter of the water to complete the reaction is 114,4mg.

Answer 2

For to know chemical equivalence must be tranform gram to moles (PM_(Mg(HCO3)2)=146,34g/mol):

moles of Mg(HCO₃)₂ =1,68mol

For to know equivalents mass of CaO (PMCaO=56,08g/mol)

are required 94,21g of CaO to be chemical equivalent.

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