Question

In: Physics

A geostationary satellite orbits the Earth in 24h, so that it appears to be at a...

A geostationary satellite orbits the Earth in 24h, so that it appears to be at a fixed position above an observer on Earth. Find its distance from Earth and its velocity by equating the gravitational pull on the satellite to its centrifugal force (GME=4 x1014 m3 /sec2 ). A precise atomic clock is present on that satellite. Use special relativity to estimate the time difference after a year between this clock and a similar one on Earth. Which clock is lagging behind the other? In a GPS system the time difference between the time t1 measured by a ground clock and the time t2 sent from an orbiting clock is used to estimate the distance between the two clocks ( l = c (t1-t2)). What error in distance results from special relativity effects on the time sent by the orbiting clock after one year?

Solutions

Expert Solution

Since the distance of geostationary satellite from earth is not given and the fact that velocity of geostationary satellite can be found by other more accurate method the answers obtained here and practiacal values may vary, if you want to know other methods I can show you, just comment on this solution and give me feedbacks.


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