Question

In: Physics

A sign (mass 2200 kg ) hangs from the end of a vertical steel girder with...

A sign (mass 2200 kg ) hangs from the end of a vertical steel girder with a cross-sectional area of 0.12 m2 .

A)What is the stress within the girder? Express your answer using two significant figures.

B)What is the strain on the girder? Use Esteel=2.0×1011N/m2 Express your answer using two significant figures.

C)If the girder is 6.50 m long, how much is it lengthened? (Ignore the mass of the girder itself.) Express your answer using two significant figures.

Solutions

Expert Solution

Given:

  • Mass of the sign :
  • Cross sectional area :
  • Modulus of elasticity for steel :
  • Acceleration due to gravity :

A) Stress within the girder :-

Stress is defined as the force per unit area,

This is the stress within the girder.

. . .

B) Strain on the girder :-

Strain is given by,

This is the strain on the girder.

​​​​​​​. . .

C) Length :-

The girder is 6.50 meter long.

Elongation in length is given by,

This much the girder is get lengthened.


Related Solutions

A mass of 0.3 kg hangs motionless from a vertical spring whose length is 1.05 m...
A mass of 0.3 kg hangs motionless from a vertical spring whose length is 1.05 m and whose unstretched length is 0.40 m. Next the mass is pulled down to where the spring has a length of 1.30 m and given an initial speed upwards of 1.9 m/s. What is the maximum length of the spring during the motion that follows?
A mass of 0.3 kg hangs motionless from a vertical spring whose length is 0.88 m...
A mass of 0.3 kg hangs motionless from a vertical spring whose length is 0.88 m and whose unstretched length is 0.48 m. Next the mass is pulled down to where the spring has a length of 1.08 m and given an initial speed upwards of 1.9 m/s. What is the maximum length of the spring during the motion that follows?
(1 point) A brick of mass 8 kg hangs from the end of a spring. When...
(1 point) A brick of mass 8 kg hangs from the end of a spring. When the brick is at rest, the spring is stretched by 3920 cm. The spring is then stretched an additional 2 cm and released with a downward force of F(t)=143cos(6t) NF(t)=143cos⁡(6t) N acts on it. Assume there is no air resistance. Note that the acceleration due to gravity, gg, is g=980g=980 cm/s22. Find the spring constant  N/cm Set up a differential equation that describes this system....
5. A car weighs 2200 lbs. Its mass is a. 2.2 kg b. 2200 kg c....
5. A car weighs 2200 lbs. Its mass is a. 2.2 kg b. 2200 kg c. 9.8 kg d. 1000 kg 6. The weight of an object a. is related to the quantity of matter it contains b. is essentially the same as its mass but expressed in different units c. is the force with which it is attracted to the Earth d. remains unchanged as the height varies 7. The action and reaction forces referred to in the third...
A 5.11-kg ball hangs from the top of a vertical pole by a 2.33-m-long string. The...
A 5.11-kg ball hangs from the top of a vertical pole by a 2.33-m-long string. The ball is struck, causing it to revolve around the pole at a speed of 4.47 m/s in a horizontal circle with the string remaining taut. Calculate the angle, between 0° and 90°, that the string makes with the pole. Take g = 9.81 m/s2.
A 5.47-kg ball hangs from the top of a vertical pole by a 2.13-m-long string. The...
A 5.47-kg ball hangs from the top of a vertical pole by a 2.13-m-long string. The ball is struck, causing it to revolve around the pole at a speed of 4.75 m/s in a horizontal circle with the string remaining taut. Calculate the angle, between 0° and 90°, that the string makes with the pole. Take g = 9.81 m/s2. Answer in degrees. What is the tension of the string? Answer in N
A single mass m1 = 3.5 kg hangs from a spring in a motionless elevator. The...
A single mass m1 = 3.5 kg hangs from a spring in a motionless elevator. The spring is extended x = 15 cm from its unstretched length. Spring constant is 228.9 2) What is the distance the lower spring is stretched from its equilibrium length? 3) Now the elevator is moving downward with a velocity of v = -2.7 m/s but accelerating upward with an acceleration of a = 5.5 m/s2. (Note: an upward acceleration when the elevator is moving...
1. A 12.0 kg sign is to be hung from the end of a uniform horizontal...
1. A 12.0 kg sign is to be hung from the end of a uniform horizontal beam of length 2.50 m and mass 55.0 kg. A vertical wire supports the beam near the end where the sign is located, and a pin attaches the beam to a wall on the opposite end of the beam. (a) If the pin can withstand a maximum force of 100 N, find the minimum distance from the wall that the vertical wire can be...
In constructing a large mobile, an artist hangs an aluminum sphere of mass 5.1 kg from...
In constructing a large mobile, an artist hangs an aluminum sphere of mass 5.1 kg from a vertical steel wire 0.51 m long and 2.4×10−3 cm2 in cross-sectional area. On the bottom of the sphere he attaches a similar steel wire, from which he hangs a brass cube of mass 11.3 kg . A- Compute the tensile strain for the top wire. Express your answer using two significant figures. B- Compute the tensile strain for the bottom wire. Express your...
A metal sphere hangs from a string and has 2 kg of mass. The sphere has...
A metal sphere hangs from a string and has 2 kg of mass. The sphere has a charge of +5.5
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT