In: Math
(a) Suppose that Marks Man is shooting at a target, where the
center of the target is at (0, 0) in the
plane. Let fX,Y (x, y) be the joint PDF of his shot. Assume that X
and Y are independent random variables,
each distributed as N (0, 1). What is P(X ≥ 0, Y ≥ 0)? (Write your
answer as a decimal).
(b) Now suppose Joe Schmo is shooting at the same target, and
let fX,Y (x, y) be the joint PDF of his
shot. Assume that X and Y are independent random variables, each
distributed as N (−1, 4) (He tends to
miss down and to the left, with a higher variance of his shots.)
What is P(X ≥ 1, Y ≥ 0)? (Write your
answer as a decimal).
(a) X,Y are independent random each distributed as N(0,1)-Standard normal distribution
therefore,
fX,Y(x,y) = fX(x)fY(y)
P(X0,Y
0)
= P(X
0)P(Y
0)
For Standard normal distributions, (P(X0)=P(Y
0)
= 0.5
P(X0,Y
0)
= P(X
0)P(Y
0)=
0.5 x 0.5=0.25
P(X0,Y
0)
= 0.25
(b) X,Y are independent random each distributed as N(-1,4) i.e mean = -1 and variance =4; standard deviation =2
therefore,
fX,Y(x,y) = fX(x)fY(y)
P(X1,Y
0)
= P(X
1)P(Y
0)
P(X1)
=1 - P(X<1)
Z-score for X=1 = (1-mean)/Standard deviation = (1-(-1))/2 = 2/2 =1
From standard normal tables, P(Z<1) = 0.8413
P(X<1) =P(Z<1) = 0.8413
P(X1)
=1 - P(X<1) = 1-0.8413=0.1587
P(Y0)
=1 - P(Y<0)
Z-score for Y=0 = (1-mean)/Standard deviation = (0-(-1))/2 = 1/2 =0.5
From standard normal tables, P(Z<0.5) = 0.6915
P(Y<0) =P(Z<0.5) =0.6915
P(Y0)
=1 - P(Y<0) = 1-0.6915=0.3085
P(X1,Y
0)
= P(X
1)P(Y
0)
= 0.1587 x 0.3085 = 0.04895895
P(X1,Y
0)
= 0.04895895