Question

In: Operations Management

Sampling 4 pieces of​ precision-cut wire​ (to be used in computer​ assembly) every hour for the...

Sampling 4 pieces of​ precision-cut wire​ (to be used in computer​ assembly) every hour for the past 24 hours has produced the following​ results:

Hour   Xbar   R   Hour   Xbar   R   Hour   Xbar   R   Hour   Xbar   R
1 3.15   0.76   7   3.15   0.53   13   3.11   0.90   19   3.31   1.66
2 3.10   1.13   8   2.65   1.08   14   2.73   1.31   20   2.89   1.14
3 3.12   1.48   9 3.12 0.71 15   3.02   1.11   21   2.65   1.08
4 3.49   1.31   10   2.95 1.38 16   2.84   0.45   22   3.18   0.46
5 3.17   1.22   11   2.73 1.17   17   2.76   1.38 23   2.84   1.53
6 2.86   0.37   12 2.87 0.35   18   2.74   1.24   24   2.74 1.02

Based on the sampling​ done, the control limits for ​3-sigma x overbarx chart are ​(round all intermediate calculations to three decimal places before proceeding with further​calculations)​:
Upper Control Limit ​(UCL Subscript x overbarUCLx​) ​= ?
Lower Control Limit ​(LCL Subscript x overbarLCLx​) ​= ?
Based on the x overbarx​-chart, the wire cutting process has been
IN CONTROL or OUT OF CONTROL?

The control limits for the ​3-sigma​ R-chart are ​(round all intermediate calculations to three decimal places before proceeding with further ​calculations)​:
Upper Control Limit ​(UCL Subscript Upper RUCLR​) ​= ?
Lower Control Limit ​(LCL Subscript Upper RLCLR​) ​= ?
Based on the​ R-chart, the wire cutting process has been
IN CONTROL or OUT OF CONTROL ?

Solutions

Expert Solution

Answer:

Based on the data available “X double overbar” and “R overbar” is to be calculated:

Sample

Average (X overbar)

Range (R )

1

3.15

0.76

2

3.1

1.13

3

3.12

1.48

4

3.49

1.31

5

3.17

1.22

6

2.86

0.37

7

3.15

0.53

8

2.65

1.08

9

3.12

0.71

10

2.95

1.38

11

2.73

1.17

12

2.87

0.35

13

3.11

0.9

14

2.73

1.31

15

3.02

1.11

16

2.84

0.45

17

2.76

1.38

18

2.74

1.24

19

3.31

1.66

20

2.89

1.14

21

2.65

1.08

22

3.18

0.46

23

2.84

1.53

24

2.74

1.02

2.965

1.032

X double overbar

R overbar

X double overbar = Average of Mean of sample 1 to 15 = 2.965

R overbar = Average of Range of sample 1 to 15 = 1.032

For sample size of 4, following will be the control constants:

Sample size

4

A2

0.729

D3

0

D4

2.282

X bar control chart:

UCL = X double overbar + A2*R bar = 2.965+(0.729*1.032) = 3.718

LCL = X double overbar - A2*R bar = 2.965-(0.729*1.032) = 2.213

Therefore,

Upper Control Limit ​(UCL Subscript x overbarUCLx​) ​= 3.718

Lower Control Limit ​(LCL Subscript x overbarLCLx​) ​= 2.213

Populate the data as under:

X bar chart


Based on the x overbar x​-chart, the wire cutting process has been IN CONTROL (as all X over bar values all within UCL & LCL).

R over bar chart:

UCL = D4*R bar = 2.282*1.032 = 2.355

LCL = D3*R bar = 0*1.032 = 0

Therefore,

Upper Control Limit ​(UCL Subscript Upper RUCLR​) ​= 2.355
Lower Control Limit ​(LCL Subscript Upper RLCLR​) ​= 0

Populate the data as under:

R overbar chart:


Based on the​ R-chart, the wire cutting process has been
IN CONTROL or OUT OF CONTROL ?

Based on the R-chart, the wire cutting process has been IN CONTROL (as all X over bar values all within UCL & LCL).


Related Solutions

S6.6 Sampling four pieces of precision cut wire( to be used in computer assembly) every hour...
S6.6 Sampling four pieces of precision cut wire( to be used in computer assembly) every hour for past 24 hours has produced the following results: hour xbar R HOUR XBAR R 1 3.25CM 0.71CM 13 3.11CM 0.85CM 2 3.10 1.18 14 2.83 1.31 3 3.22 1.43 15 3.12 1.06 4 3.39 1.26 16 2.84 0.50 5 3.07 1.17 17 2.86 1.43 6 2.86 0.32 18 2.74 1.29 7 3.05 0.53 19 3.41 1.61 8 2.65 1.13 20 2.89 1.09 9...
Consider a wire of length 4 ft that is cut into two pieces. One pieces form...
Consider a wire of length 4 ft that is cut into two pieces. One pieces form a radius for circle and other forms a square of side x. 1) choose x to maximize the sum of area. 2) choose x to minimize the sum of their areas. WHERE I got x=4/(x+pie).But i am not sure...
A 20 foot piece of wire is to be cut into two pieces. One piece is...
A 20 foot piece of wire is to be cut into two pieces. One piece is used to form a circle and the other is used to form a square (imagine fence used to make a square corral and a circular corral). What lengths should be cut to make each shape in order to maximize the sum of the areas of the two shapes? Let x = the length of the part of the wire that will be used to...
A wire of length 30 cm is cut into 2 pieces which are then bent into...
A wire of length 30 cm is cut into 2 pieces which are then bent into the shape of a circle of radius r and an equilateral triangle with side length s. Find the value of r which minimizes the total area enclosed by both shapes
A piece of wire of length 50 is​ cut, and the resulting two pieces are formed...
A piece of wire of length 50 is​ cut, and the resulting two pieces are formed to make a circle and a square. Where should the wire be cut to​ (a) minimize and​ (b) maximize the combined area of the circle and the​ square? a) To minimize the combined​ area, the wire should be cut so that a length of ____ is used for the circle and a length of ____is used for the square. ​(Round to the nearest thousandth...
A wire 370 in. long is cut into two pieces. One piece is formed into a...
A wire 370 in. long is cut into two pieces. One piece is formed into a square and the other into a circle. If the two figures have the same area, what are the lengths of the two pieces of wire (to the nearest tenth of an inch)?
A wire 370 in. long is cut into two pieces. One piece is formed into a...
A wire 370 in. long is cut into two pieces. One piece is formed into a square and the other into a circle. If the two figures have the same area, what are the lengths of the two pieces of wire (to the nearest tenth of an inch)?
consider the following function. A piece of wire 14 m long is cut into two pieces....
consider the following function. A piece of wire 14 m long is cut into two pieces. One piece is bent into a square and one bent into an equilateral triangle. How should the wire be cut so that the total area enclosed is a minimum?
A piece of wire 10 meters long is cut into two pieces. One piece is bent...
A piece of wire 10 meters long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral triangle. How should the wire be cut so that the total area enclosed is: a maximum? a minimum?
A piece of wire 6 m long is cut into two pieces. One piece is bent...
A piece of wire 6 m long is cut into two pieces. One piece is bent into a square and the other is bent into a circle. (a) How much wire should be used for the square in order to maximize the total area? (b) How much wire should be used for the square in order to minimize the total area?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT