In: Statistics and Probability
The mean amount purchased by each customer at Churchill’s Grocery Store is $27 with a standard deviation of $9. The population is positively skewed. For a sample of 48 customers, answer the following questions:
a. What is the likelihood the sample mean is at least $29? (Round the z-value to 2 decimal places and the final answer to 4 decimal places.)
b. What is the likelihood the sample mean is greater than $26 but less than $29? (Round the z-value to 2 decimal places and the final answer to 4 decimal places.) c. Within what limits will 98% of the sample means occur? (Round the final answers to 2 decimal places.)
Since the sample size is 48 >30, we can use the CLT and approximate the distribution of the sample mean to be normal i.e.
i.e.
i.e.
i.e.
a.
We need to compute
. The corresponding z-value needed to be computed is:
Therefore, we get that
The following is obtained graphically:
b.
The following is obtained graphically:
c.
98% of the sample means will lie between
Calculated as:
The following is obtained graphically:
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