In: Statistics and Probability
A town’s December high temperatures average 46 oF with a standard deviation of 9 oF, while in June the mean height temperature is 75 oF with a standard deviation of 8 oF. In which month is it more unusual to have a high temperature of 64 oF?
a. |
June because the z-score is farther away from zero than for December |
|
b. |
June because the z-score is closer to zero than for December. |
|
c. |
December because the z-score is closer to zero than for June. |
|
d. |
December because the z-score is farther away from zero than for June. |
solution:
Let X be the ranom representing temperature in a town
i) Given that In the month of december
Mean = = 46
Standard Deviation = = 9
For 64 oF
z-score is z1 =
=
= 2
Here,Probability that in december has 64 (or) more degrees = P(z>=2)
= 1- P(z<=2)
= 1- 0.9772 [ use normal distribution table ]
= 0.0228
i) Given that In the month of June
Mean = = 75
Standard Deviation = = 8
For 64 oF
z-score is z1 =
=
= -1.375
Here,Probability that in december has 64 (or) more degrees = P(z>=-1.375)
= P(z<=1.375)
= 0.9154 [ use normal distribution table ]
= 0.9154
Here December has more unusual to have high temperature of 64. since ,Observe that In december P(64 (or) more degrees ) < 0.05 and it's z-score (2) is farther away from zero than for june (-1.375)
Therefore, Option-D is correct