Question

In: Statistics and Probability

A town’s December high temperatures average 46 oF with a standard deviation of 9 oF, while...

A town’s December high temperatures average 46 oF with a standard deviation of 9 oF, while in June the mean height temperature is 75 oF with a standard deviation of 8 oF. In which month is it more unusual to have a high temperature of 64 oF?

a.

June because the z-score is farther away from zero than for December

b.

June because the z-score is closer to zero than for December.

c.

December because the z-score is closer to zero than for June.

d.

December because the z-score is farther away from zero than for June.

Solutions

Expert Solution

solution:

Let X be the ranom representing temperature in a town

i) Given that In the month of december

Mean = = 46

Standard Deviation = = 9

For 64 oF

z-score is z1 =

=

= 2

Here,Probability that in december has 64 (or) more degrees = P(z>=2)

= 1- P(z<=2)

= 1- 0.9772 [ use normal distribution table ]  

= 0.0228

i) Given that In the month of June

Mean = = 75

Standard Deviation = = 8

For 64 oF

z-score is z1 =

=

= -1.375

Here,Probability that in december has 64 (or) more degrees = P(z>=-1.375)

= P(z<=1.375)

= 0.9154 [ use normal distribution table ]  

= 0.9154

Here December has more unusual to have high temperature of 64. since ,Observe that In december P(64 (or) more degrees ) < 0.05 and it's z-score (2) is farther away from zero than for june (-1.375)

Therefore, Option-D is correct


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