In: Statistics and Probability
1. Find the standard deviation, s, of sample data summarized in the frequency distribution table given below by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values 9.0
s=∑f•x2−∑(f•x)2n(n−1)
Interval |
30-36 |
37-43 |
44-50 |
51-57 |
58-64 |
65-71 |
|
---|---|---|---|---|---|---|---|
Frequency |
2 |
17 |
39 |
19 |
10 |
1 |
Standard deviation = ?
(Round to one decimal place as needed.)
2. Heights of men on a baseball team have a bell-shaped distribution with a mean of 170 cm and a standard deviation of 5 cm. Using the empirical rule, what is the approximate percentage of the men between the following values?
a.---------% of the men are between 160 cm and 180 cm.
b.----------%of the men are between 155 cm and 185 cm.
(1)
From the given data, the following Table is calculated:
Class | Frequency (f) | Mid point (x) | f x | f x2 |
30 - 36 | 2 | 33 | 66 | 2178 |
37 - 43 | 17 | 40 | 680 | 27200 |
44 - 50 | 39 | 47 | 1833 | 86151 |
51 - 57 | 19 | 54 | 1026 | 55404 |
58 - 64 | 10 | 61 | 610 | 37210 |
65 - 71 | 1 | 68 | 68 | 4624 |
Total = | n = = 88 |
Sample Standard Deviation (s) is given by:
So,
Standard Deviation = 7.0
(2)
(a)
= 170
= 5
X = 160
So,
Z = (160 - 170)/5
= - 2
X = 180
So,
Z = (180 - 170)/5
=2
So,
Using empirical rule:
95.45 % of the men are between 160 cm and 180 cm.
(b)
= 170
= 5
X = 155
So,
Z = (155 - 170)/5
= - 3
X = 185
So,
Z = (185 - 170)/5
= 3
So,
Ubsing empirical rule:
99.73 % of the men are between 155 cm and 185 cm.