Question

A nutritionist claims that the mean tuna consumption by a person is 3.9 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.7 pounds per year. Assume the population standard deviation is 1.02 pounds. At alphaαequals=0.07 can you reject the​ claim?

Answer 1

Given :

Claim : The mean tuna consumption by a person is 3.9 pounds per year .

Null and alternative hypothesis :

(claim)

As the population standard deviation is known we use z-test .

Test statistic :

Using excel function , =NORMSDIST(z)

=NORMSDIST(-1.64)

=0.0505

As the alternative hypothesis is of note equal to ( ≠ ) type this is two tailed test .

So p-value = 2 * 0.0505 = 0.1010

p-value = 0.1010

Decision rule :

If p-value is less than the significance level () , then we reject the null hypothesis (Ho).

Since p-value 0.1010 is greater than the significance level alpha=0.07 , we fail to reject the null hypothesis (Ho).

Therefore we fail to reject the claim .