Question

4 questions about social statistic

test scores of students : 66 89 47 63 40 51 62 80 60 97 48 64 67 97 60 67 81 64 74 38 69 50 59 80 57 33 47 72 68 91 74 47 73 50 52 43 54 98 54 63 79 33 51 54 60 44 82 43 32 48 46 57 47 92 72 87 71 79 84 41 40 58 44 61 38 92 71 41 83 84

What % of students received the high est score and the low est score?

What % of students received the most c ommon score?

What score did the students receive on average ? (I need statistical formula and process of calculation)

What score did almost half of th e students receive ? (I need statistical formula and process of calculation)

Answer 1

SOLUTION:

TOTAL NO OF SCORES= 70

HIGHEST SCORE= 98

LOWEST SCORE= 32

A.) PERCENTAGE OF STUDENTS RECEIVED HIGHEST SCORE(i.e, 98)= (1/70*100) = 1.43%

PERCENTAGE OF STUDENTS RECEIVED LOWEST SCORE(i.e, 32)= (1/70*100) = 1.43%

  [#THE QUESTION WAS NOT CLEAR SO I AM ALSO COMPUTING THE PERCENTAGE OF STUDENTS RECEIVING HIGHEST AND LOWEST SCORE= (2/70*100) = 2.86%]

B.) THE MOST COMMON SCORE IS 47 WHICH HAS OCCURED 4 TIMES.

HENCE, PERCENTAGE OF STUDENTS WHO RECEIVED MOST COMMON SCORE IS (4/70*100) = 5.71%

C.) THE FORMULA TO CALCULATE AVERAGE OF THE SCORES IS , where n=70.

WE USE MINITAB 16 TO COMPUTE THE AVERAGE SCORE OF THE STUDENTS-

ENTER THE SCORES IN A SINGLE COLUMN>STAT>BASIC STATISTICS>DISPLAY BASIC STATISTICS>SELECT THE COLUMN UNDER VARIANLES>IN STATISTICS, SELECT MEAN>OK

THE AVERAGE SCORE= 62.33

D.) TO FIND THE SCORE THAT HALF OF THE STUDENTS RECEIVE, WE COMPUTE MEDIAN

AS N=70(EVEN), MEDIAN IS COMPUTED AS

  WE USE MINITAB 16 TO COMPUTE THE MEDIAN SCORE OF THE STUDENTS-

  ENTER THE SCORES IN A SINGLE COLUMN>STAT>BASIC STATISTICS>DISPLAY BASIC STATISTICS>SELECT THE COLUMN UNDER VARIANLES>IN STATISTICS, SELECT MEDIAN>OK

HENCE, THE MEDIAN SCORE= 60.50

REMARK- THE NEEDED WORKOUT IS SHOWN ABOVE. IN CASE OF DOUBT, COMMENT BELOW. AND DO LIKE, IF POSSIBLE.