In: Statistics and Probability
With descriptive statistics you are simply describing what is or what the data shows. With inferential statistics, you are trying to reach conclusions that extend beyond the immediate data alone. For instance, we use inferential statistics to try to infer from the sample data what the population might think
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µ= 500
σ= 100
X= 520
Z=(X-µ)/σ= (520-500)/100)=
0.2
...........
x = 650
Z=(X-µ)/σ= (650-500)/100)= 1.5
.....
x=500
Z=(X-µ)/σ= (500-500)/100)=
0
......
x = 450
Z=(X-µ)/σ= (450-500)/100)=
-0.5
.........
x = 280
Z=(X-µ)/σ= (280-500)/100)=
-2.2
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normal probaility distribution :
is a type of continuous probability distribution for a real-valued random variable. The general form of its probability density function is
A normal distribution is sometimes informally called a bell curve
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In probability theory, a probability density function (PDF),of a continuous random variable, is a function whose value at any given point in the sample space can be interpreted as providing a relative likelihood that the value of the random variable would equal that sample
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In statistics, a sampling distribution or finite-sample distribution is the probability distribution of a given random-sample-based statistic.
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Systematic sampling is a type of probability sampling method in which sample members from a larger population are selected according to a random starting point but with a fixed, periodic interval. This interval, called the sampling interval, is calculated by dividing the population size by the desired sample size
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Ho: p1 - p2 = 0
Ha: p1 - p2 ╪ 0
sample #1 ----->
experimental
first sample size, n1=
142
number of successes, sample 1 = x1=
9
proportion success of sample 1 , p̂1=
x1/n1= 0.0634
sample #2 -----> standard
second sample size, n2 =
268
number of successes, sample 2 = x2 =
5
proportion success of sample 1 , p̂ 2= x2/n2 =
0.019
difference in sample proportions, p̂1 - p̂2 =
0.0634 - 0.0187 =
0.0447
pooled proportion , p = (x1+x2)/(n1+n2)=
0.0341
std error ,SE = =SQRT(p*(1-p)*(1/n1+
1/n2)= 0.0188
Z-statistic = (p̂1 - p̂2)/SE = (
0.045 / 0.0188 ) =
2.3726
p-value = 0.0177 [excel
formula =2*NORMSDIST(z)]
decision : p-value<α,Reject null hypothesis
there is significant difference
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i have done all
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