In: Computer Science
We want to make Error detection method, the even parity method. the input is 3bit binary, output is 1 bit of even parity bit.
if the 3 bit is 111 or 000 it is disable, other else are enable. we have to add this in even parity method.
if it is enable, the output 1 bit of even parity method will show.
if it is disable the output will be 0
(the gate must be maximum 4 bit input, and the number of gates must be at least)
draw the circuits
Please check out the solution of the given problem and the circuit diagram which is done in logism platform... for any kind of doubt, please leave a comment...Thank you...
Even parity checks that if the number of 1 in the code is odd, in parity bit, 1 is assignes to make the number of 1 even... if the number of 1 in the code is already even, then 0 is assigned to the parity bit...
for this question, we have to calculate the parity bit as
output...
pre condition : if the input is 000 or 111 the the parity
bit/output is disable i.e. 0
Note: here 3 bit input gates are used.. which is less than 4 bit input gates..Toata(minimum) gates required =7
Truth Table and Boolean expression:
circuit diagram