Question

(JAVA)
For your homework, I want you to create the order of your mini-programs based on how it is listed in this assignment description (i.e., Program 1 should be the first program implemented, Program 2 should be the second program, etc.). All your mini-programs are housed inside one main method. The name of your class for this homework should be called Homework3. You will be submitting that single Java file to this submission box. There are a total of two mini-programs you have to implement, and each program is worth 40 points for functioning code and correct outputs. Altogether, the programs are 80 points in total; the remaining 20 points reflect your programming style and documentation.

Program 1 - Palindrome

A palindrome is a sequence of characters that reads the same backward as forward. For example, each of the following five-digit integers is a palindrome: 12321, 55555, 45554, and 11611. Write an application that reads in a five-digit integer and determines whether it's a palindrome. If the number is not five digits long, display an error message and allow the user to enter a new value.

Sample Input
Enter a number: 11611

Sample Output
11611 is a palindrome.

Sample Input
Enter a number: 55953

Sample Output
55953 is not a palindrome.

Sample Input
Enter a number: 1151
Enter a number: 3920
Enter a number: 12321

Sample Output
12321 is a palindrome.

Sample Input
Enter a number: 116611
Enter a number: 999999
Enter a number: 99989

Sample Output
99989 is not a palindrome.

Program 2 - Printing the Decimal Equivalent of a Binary Number

Write an application that inputs an integer containing only 0s and 1s (i.e., a binary integer) and prints its decimal equivalent. [Hint: Use the remainder and division operators to pick off the binary number's, digits one at a time, from right to left. In the decimal number system, the rightmost digit has a positional value of 1 and the next digit to the left a positional value of 10, then 100, then 1000, and so on. The decimal number 234 can be interpreted as 4 * 1 + 3 * 10 + 2 * 100. In the binary number system, the rightmost digit has a positional value of 1, the next digit to the left a positional value of 2, then 4, then 8, and so on. The decimal equivalent of binary 1101 is 1* 1 + 0 * 2 + 1 * 4 + 1 * 8, 1 + 0 + 4 + 8, or 13]

Sample Input
Enter a binary number: 1101

Sample Output
13 is the decimal equivalent of 1101

Sample Input
Enter a binary number: 1000110

Sample Output
70 is the decimal equivalent of 1000110

Sample Input
Enter a binary number: 11111111

Sample Output
255 is the decimal equivalent of 11111111

Sample Input
Enter a binary number: 1001001110

Sample Output
590 is the decimal equivalent of 1001001110

Answer 1

Below is the solution:

code:

import java.util.Scanner;

public class Homework3 {
   public static void main(String[] args) {
       Scanner input = new Scanner(System.in); // scanner class
       int number, temp, remainder, sum = 0; // declare the variabel
       // input number
       System.out.print("Enter a number: ");
       number = input.nextInt();
       // loop until user enter the 5 digit number
       while (number < 10000) { // number is less than 5 digit long
           System.out.print("Enter a number: ");
           number = input.nextInt();
       }
       temp = number;
       // reverse the number
       while (number > 0) {
           remainder = number % 10; // take remainder
           sum = (sum * 10) + remainder;
           number = number / 10;
       }
       // check for the temp not equal to sum
       if (temp != sum)
           System.out.println(temp + " is not a palindrome.");
       else
           System.out.println(temp + " is a palindrome.");
   }
}

sample input:

Enter a number: 1151
Enter a number: 3920
Enter a number: 12321

sample output:

12321 is a palindrome.

import java.util.Scanner;

public class BinaryToDecimal {
   public static void main(String[] args) {
       Scanner input = new Scanner(System.in); // scanner class
       int number;// declare the variable
       int decimal = 0;
       int n = 0;
       // input binary number
       System.out.print("Enter a binary number: ");
       number = input.nextInt();
       int tempNumber = number;
       while (true) {
           if (number == 0) {
               break;
           } else {
               int temp = number % 10; // get the remainder
               decimal += temp * Math.pow(2, n); // calculate the remainder and add to the decimal
               number = number / 10;
               n++;
           }
       }
       // display
       System.out.println(decimal + " is the decimal equivalent of " + tempNumber);
   }
}

sample input:

Enter a binary number: 1101

sample output:

13 is the decimal equivalent of 1101