Question

Design an IP Addressing Scheme; please provide explanation with the answers

Subnet the 192.168.1.0 network into the appropriate number of subnets.

1. What will be the subnet mask be for the subnetworks?
2. How many usable host IP addresses are there per subnet?
3. Fill in the following chart with the subnet information

Subnet Number	Subnet Address	1st Usable Host Address	Last Usable Host Address	Broadcast Address

Answer 1

1. The ip address is 192.168.1.0 .Class A 0-127,Class B 128-191,Class C 192-223.Generally the ip Address resides in Class C.

At first to get the subnet mask of this IP we have to convert it into binary:

11000000 10101000 00000001 00000000

as this is Class C ,the subnet mask will be

11111111 11111111 11111111 00000000

so the netmask for this ip address 255.255.255.0

2.The number of usable host ip addresses will be 2^8 - 2=254 (2 ip addresses will be engaged by broadcast address and loopback address)

3.

Subnet Number	Subnet Address	1st usable host address	Last Usable host address	Broadcast Address
192.168.1.0/24	192.168.1.0	192.168.1.1	192.168.1.254	192.168.1.255

The first Adress 192.168.1.0 and the last adress 192.168.1.255 of the subnet will be engaged as the reserved adress.That is why the first usable host adress will be 192.168.1.1 and last usable host adress will be 192.168.1.254.Total adress range is 0-255. Total 256 adresses.