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In: Statistics and Probability

Can an answer, complete with workings please be provided for Problem 32E, Chapter 15 from the...

Can an answer, complete with workings please be provided for Problem 32E, Chapter 15 from the Business Statistics: Communicating with Numbers (2nd Edition) be made available?

The manager of a local Costo store is in the process of making hiring decisions for selling mobile phone contracts. She believes that the sale of mobile phone contracts depends crucially on the number of hours clocked by male and female employees. She collects the weekly data on last year’s sales of mobile phone contracts (Sale) along with work hours of male (Hours Males) and female (Hours Females) employees. A portion of the data is shown in the accompanying table.

a.

Report the sample regression equation of the appropriate model.

b.

At the 5% significance level, are the explanatory variables jointly significant? Are they individually significant? Use the p-value approach for the tests.

c.

The manager would like to determine whether there is a difference in productivity of male and female employees. In other words, for the same work hours, whether the number of sales of mobile contracts varies between male and female employees. Conduct the appropriate test at the 5% level of significance. Provide the details.

Sale Hours Males Hours Females
59 30 32
65 33 36
62 27 34
61 28 34
65 33 37
63 33 35
55 27 29
61 25 38
63 31 34
63 32 35
59 28 29
63 34 34
64 35 34
61 26 35
62 30 33
61 31 33
62 29 34
62 31 32
62 29 34
63 33 32
65 33 36
59 30 29
62 30 35
59 28 33
61 31 32
61 30 35
65 35 32
62 29 34
56 24 31
63 29 36
64 28 34
59 29 33
63 27 36
61 30 35
64 32 35
62 29 34
56 26 32
63 29 35
63 27 37
63 32 34
64 28 38
59 24 33
61 28 35
64 31 34
64 32 36
65 31 35
62 28 36
63 33 34
65 32 36
61 29 36
61 30 34
64 35 35

Solutions

Expert Solution

a)

Here i write R-code for given problem as:

s=c(59,65,62,61,65,63,55,61,63,63,59,63,64,61,62,61,62,62,62,63,65,59,62,59,61,61,65,62,56,63,64,59,63,61,64,62,56,63,63,63,64,59,61,64,64,65,62,63,65,61,61,64)
m=c(30,33,27,28,33,33,27,25,31,32,28,34,35,26,30,31,29,31,29,33,33,30,30,28,31,30,35,29,24,29,28,29,27,30,32,29,26,29,27,32,28,24,28,31,32,31,28,33,32,29,30,25)
f=c(32,36,34,34,37,35,29,28,34,35,29,34,34,35,33,33,34,32,34,32,36,29,35,33,32,35,32,34,31,36,34,33,36,35,35,34,32,35,37,34,38,33,35,34,36,35,36,34,36,36,34,35)
d=data.frame(s,m,f)
d
a=aov(s~f+m+f*m,d)
summary(a)

And the output is;

summary(a)
Df Sum Sq Mean Sq F value Pr(>F)   
f 1 114.41 114.41 52.692 2.95e-09 ***
m 1 59.04 59.04 27.192 3.87e-06 ***
f:m 1 0.01 0.01 0.005 0.944   
Residuals 48 104.23 2.17
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

b)

Here both p-values are less than 0.05, thus the explainitory variable is jointly significant.
And the interaction effect is insignificant.

c)

H0: Their is no difference in productivity of male and female employee.
H1: Their is difference in productivity of male and female employee.

Here the R-code is as follows;

m=c(30,33,27,28,33,33,27,25,31,32,28,34,35,26,30,31,29,31,29,33,33,30,30,28,31,30,35,29,24,29,28,29,27,30,32,29,26,29,27,32,28,24,28,31,32,31,28,33,32,29,30,25)
f=c(32,36,34,34,37,35,29,28,34,35,29,34,34,35,33,33,34,32,34,32,36,29,35,33,32,35,32,34,31,36,34,33,36,35,35,34,32,35,37,34,38,33,35,34,36,35,36,34,36,36,34,35)
t.test(m,f)


And the output is,


Welch Two Sample t-test

data: m and f
t = -8.9488, df = 96.51, p-value = 2.59e-14
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-5.169160 -3.292378
sample estimates:
mean of x mean of y
29.69231 33.92308

Here, p-value is less than 0.05, thus we reject H0 at 5% l.o.s.


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