Question

The Sum and The Average

In C++,

Write a program that reads in 10 integer numbers. Your program should do the following things:

Use a Do statement

Determine the number positive or negative

Count the numbers of positive numbers, and negative

Outputs the sum of:

all the numbers greater than zero

all the numbers less than zero (which will be a negative number or zero)

all the numbers

Calculate the average of all the numbers.

The user enters the ten numbers just once each and the user can enter them in any order. Your program should not ask the user to enter the positive numbers and the negative numbers separately

Answer 1

#include <iostream>
using namespace std;

int main() {
int a[10], i = 0;
int positive = 0, negative = 0, posSum = 0, negSum = 0;

cout << "Enter 10 numbers:\n";
do{
cin >> a[i];
if(a[i] > 0)
{
positive++;
posSum += a[i];
}
else
{
negative++;
negSum += a[i];
}
i++;
}while(i < 10);

cout << "Sum of numbers > 0 = " << posSum << endl;
cout << "Sum of numbers <= 0 = " << negSum << endl;
cout << "Sum of all numbers = " << posSum + negSum << endl;
cout << "Average = " << (posSum + negSum)/10.0;
}

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