Question

School	% free or Reduced	Attendance Rate
1	70.3	92.8
2	53.4	94.6
3	48.3	94.2
4	62.7	93.8
5	66.0	94.0
6	69.2	91.9
7	76.0	93.7
8	65.9	95.1
9	62.9	95.3
10	49.6	96.8
11	79.7	91.7
12	71.7	93.1
13	57.2	95.4
14	65.0	93.6
15	59.9	94.8
16	63.9	94.8
17	62.4	93.7
18	66.0	93.4
19	69.2	93.8
20	63.3	93.6

Please use SPSS so I can Check my answer see they are correct . Thanks

1. What is the mean percent of students receiving free or reduced lunch? What is the mean attendance rate?

2. What are the standard deviations for the percent of students receiving free or reduced lunch and attendance rate?

3 State an appropriate null hypothesis for this analysis

4. What is the value of correlation coefficient?

5. Based on the value of the correlation coefficient, how would you classify the strength of this relationship?

6. Based on the information from the scenario, what is the appropriate value for the degrees of freedom?

7. What is the reported level of significance?

8 Present the result as they might appear in an article. This must include a table and narrative statement that reports and interprets the results of your analysis.

Answer 1

1) The mean percent of students receiving free or reduced lunch is 64.13 and the mean attendance rate is 94.005

2)  The standard deviations for the percent of students receiving free or reduced lunch is 7.91748 and attendance rate standard deviation is 1.19801

3) NULL HYPOTHESIS H0:

ALTERNATIVE HYPOTHESIS Ha:

4) The value of correlation coefficient is -0.715

5) Based on the value of the correlation coefficient,the strength of this relationship is moderate.

6) Degrees of freedom= n-2= 20-2=18

7) Since you have not mentioned the level of significance so I assumed it 0.01

Since P value is smaller than the level of significance therefore SIGNIFICANT.

Decision: REJECT NULL HYPOTHESIS H0.

Conclusion:We have sufficient evidence to show that there is a correlation between two variables.