Question

Do the following code by using python: ( Thank!)

You roll two six-sided dice, each with faces containing one, two, three, four, five and six spots, respectively. When the dice come to rest, the sum of the spots on the two upward faces is calculated.

• If the sum is 7 or 11 on the first roll, you win.

• If the sum is 2, 3 or 12 on the first roll (called “Mygame”), you lose (i.e., the “house” wins).

• If the sum is 4, 5, 6, 8, 9 or 10 on the first roll, that sum becomes your “point.”

To win, you must continue rolling the dice until you “make your point” (i.e., roll that same point value). You lose by rolling a 7 before making your point.

Answer 1

The Python code for the given problem is as follows -

import random

point = 0

dice1 = random.randint(1,6)
dice2 = random.randint(1,6)

#After first roll
diceSum = dice1 + dice2
if(diceSum == 7 or diceSum == 11):
    print('You Win!')
elif(diceSum == 2 or diceSum == 3 or diceSum == 12):
    print('You Lose!')
else:
    point = diceSum
    while(True):
        #Roll the dices again and agin
        dice1 = random.randint(1,6)
        dice2 = random.randint(1,6)

        if (dice1+dice2 == point):
            print('You Win')
            break
        if(dice1+dice2 == 7):
            print('You Lose')
            break

Explanation-

• dice1 and dice2 represent 2 variables that are rolled. They have a random value between 1 and 6.
• The if and elif statemtns after that check for the first and second conditions.
• In the else statement we calculate the point value and start a loop
• In the loop, we roll the dice again and again. We first check if sum equals point value then you become the winner. Else if sum equals 7 then you lose.

OUTPUT Screenshot-

We run the program multiple times and can see the different statements. To be more verbose, you can also print the diceSum value.

If you get multiple times the same value, then print and see the diceSum, which will surely be random.