In: Statistics and Probability
Question 4 [3 marks]
Four tourists plan on taking a bus tour around Toronto. This tour allows them to hop on and off the bus at any of the 8 stops available. The available stops are the CN tower, Harbour Front, Queen’s Quay, Dundas Square, Casa Loma, Distillery District, Bata Shoe Museum and the Royal Ontario Museum.
Solution
Back-up Theory
Probability of an event E, denoted by P(E) = n/N ………………...................……………(1)
where
n = n(E) = Number of outcomes/cases/possibilities favourable to the event E and
N = n(S) = Total number all possible outcomes/cases/possibilities.
Now to work out the solution,
There are 4 tourists and 8 locations. Since the same location can be visited by
more than one tourist, total number of possible location visits = 84 = 4096 ................. (2)
Hence, vide (1), N = 4096 ..............................................................................................(3)
Part (a)
Two attending one location can any 2 out of 4 tourists in 4C2 = 6 ways. Then, the two necessarily visit another location. Thus, there is only one possibility.
Now, the first pair can choose any one of 8 locations in 8 ways and then the second
pair can choose only one of the remaining 7 locations.
So, total number of possibilities = 6 x 8 x 7 = 336 and hence vide (1), n = 336 ............ (4)
Finally, vide (1), (3) and (4),
Probability that two attend one location and two attend another location = 336/4096
= 0.0820 Answer 1
Part (b)
If no tourists hop off at the Distillery District and Bata Shoe Museum, the number of
location choices reduces from 8 to 6. Hence, total number of possible location visits
= 64 = 1296 and this then becomes n vide (1)................................................................. (5)
Thus, vide (1), (3) and (5),
Probability that no tourist hop off at the Distillery District and Bata Shoe Museum
= 1296/4096
= 0.3164 Answer 2
Part (c)
Probability that at least one tourist gets off at Casa Loma
= 1 –P(no tourist gets off at Casa Loma)
No tourist gets off at Casa Loma => the number of location choices reduces from
8 to 7. Hence, total number of possible location visits = 74 = 2401 and this then
becomes n vide (1)......................................................................................................... (6)
Thus, vide (1), (3) and (6),
Probability that at least one tourist gets off at Casa Loma
= 1 – (2401/4096)
= 1 – 0.5862
= 0.4138 Answer 3
DONE