Question

In: Statistics and Probability

Please show work 5. Sears is in the process of hiring a new Manager for its...

Please show work

5. Sears is in the process of hiring a new Manager for its Monmouth Mall store and they are trying to estimate the best annual healthcare premium. In a sample of 30 Managers, they found that the average yearly premium needed is $16,469 with a standard deviation of $2,000.

(a) What is the population mean? What is the best estimate of the population mean?

(b) Develop an 95% confidence interval for the population mean.

(c) Assuming a 99% level of confidence, how large of a sample is required with an acceptable error of $600?

Solutions

Expert Solution

(a) What is the population mean? What is the best estimate of the population mean?

The best estimate of the population mean is sample mean is sample mean $16469

(b) Develop an 95% confidence interval for the population mean.

The provided sample mean is 16469 and the sample standard deviation is s = 2000 The size of the sample is n = 30 and the required confidence level is 95%.

The number of degrees of freedom are df = 30 - 1 = 29 , and the significance level is α=0.05.

Based on the provided information, the critical t-value for α=0.05 and df = 29 degrees of freedom is t_c = 2.04

The 95% confidence for the population mean μ is computed using the following expression

Therefore, based on the information provided, the 95 % confidence for the population mean μ is

CI = (15722.188, 17215.812)

(c) Assuming a 99% level of confidence, how large of a sample is required with an acceptable error of $600?

z_c = 2.58 for 99% confidence interval

Acceptable error = E = 600

s = 2000

n = 73.96

n = 74


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