In: Physics
The position of a particle is given in cm by x = (8) cos 9?t, where t is in seconds. (a) Find the maximum speed.b) Find the maximum acceleration of the particle.(c) What is the first time that the particle is at x = 0 and moving in the +x direction?
GIVEN
x = 8(cos 9?t)
<< Find the maximum speed. >>
Differentiating the given function,
dx/dt = velocity = - 64? (sin 9?t)
and the maximum speed is when
sin 9?t = - 1
9?t = arc sin -1 = 3?/2
and solving for "t",
t = 1/6
Substitute t = 1/6 in the above equation for dx/dt and this will
give you the maximum speed. I trust that you can proceed with the
actual calculations on your own.
<< Find the maximum acceleration of the particle.
>>
The second derivative of the function,
d^x/dt^2 = acceleration = - 64 pie (sin 9?t) = - 729(?)^2 (cos
9?t)
and the maximum acceleration is when cos 9?t = -1.
To determine the maximum acceleration, follow the same steps above
in determining the maximum velocity. Again, I trust that you can do
this on your own as you can simply follow the above
procedure.
<< What is the first time that the particle is at x = 0 and
moving in the +x direction? >>
When x = 0, the given function becomes
0 = (8 cm) cos 9?t
and the above becomes
cos 9?t = 0
9?t = arc cos 0
9?t = ?/2
and solving for "t"
t = 1/18