In: Statistics and Probability
Calories |
70 |
120 |
70 |
50 |
110 |
110 |
110 |
130 |
90 |
90 |
120 |
110 |
120 |
110 |
110 |
110 |
100 |
110 |
110 |
110 |
100 |
110 |
100 |
100 |
110 |
110 |
100 |
120 |
120 |
120 |
110 |
110 |
140 |
110 |
160 |
140 |
130 |
120 |
50 |
50 |
We sort the data from lowest to highest
The number of samples having 100 calories or less per serving = 12
Total number of samples = 40
Proportion of cereals that have 100 CALORIES or less per serving = 12/40 = 0.3
Given
p̂ =
0.3 .......
Sample Proportion
n =
40 .......
Sample Size
For 99% Confidence interval
α = 0.01, α/2 = 0.005
From z tables of Excel function NORM.S.INV(α/2) we find the z
value
z = NORM.S.INV(0.005) = 2.576
We take the positive value of z
Confidence interval is given by
= (0.1134, 0.4866)
99% Confidence interval for true proportion of cereals that
have 100 CALORIES or less per serving is
calories
---------------------------------------------------------------------------------------------------------------------------------
If you are satisfied with the solution, kindly give a thumbs
up.