In: Statistics and Probability
Hint: The physical program will be considered effective, if before weight is greater than after weight. Difference = Before – After
H0:
Ha:
Randomization assumption:
Normality assumption:
Note: Attach R codes and normal QQ plot in the following space:
Test statistic =
df =
p-value =
Note: Attach R codes and outputs in the following space:
Subject | Before | After |
1 | 201 | 196 |
2 | 178 | 171 |
3 | 169 | 170 |
4 | 212 | 207 |
5 | 180 | 177 |
6 | 192 | 190 |
7 | 158 | 159 |
8 | 180 | 180 |
9 | 170 | 164 |
10 | 153 | 152 |
11 | 183 | 179 |
12 | 165 | 162 |
13 | 201 | 199 |
14 | 179 | 173 |
15 | 236 | 231 |
16 | 144 | 140 |
a) The average weight before physical exercise is mu1
The average weight after physical exercise is mu2
b) H0: The physical program will be considered not
effective
H1: The physical program will be considered effective
c) Paired t - test is used since the samples are not independent
d) Normality assumption:
The distribution is follows normal distribution
e) From the given data
Test Statistic t = 5.0814
P-value = 0.000
df = 15
f) since p-value < alpha 0.05 so we reject H0
g) Thus we conclude that the physical program will be considered effective