Question

In: Statistics and Probability

In a study of the effectiveness of physical exercise in weight reduction, a group of 16...

  1. In a study of the effectiveness of physical exercise in weight reduction, a group of 16 people (randomly selected) engaged in a prescribed program of physical exercise for one month. Each subject’s weight (in pounds) is measured two times (before and after the physical exercise). The data can be found in the excel file Exercise with variables name Subject, Before, and After. At the 5% significance level, do we have sufficient evidence to conclude that the physical exercise program is effective? (21 points total)

Hint: The physical program will be considered effective, if before weight is greater than after weight. Difference = Before – After

  1. Label the Parameters: (3 points)
  1. State null and alternative hypotheses: (2 points)

H0:

Ha:

  1. Propose an appropriate hypothesis test. Explain! (4 points)
  2. Verify the required conditions for the proposed hypothesis test: (4 points)

Randomization assumption:

Normality assumption: 

Note: Attach R codes and normal QQ plot in the following space:

  1. Report a test statistic, df, and p-value. (3 points)

Test statistic =

df =

p-value =

Note: Attach R codes and outputs in the following space:

  1. Make a decision of hypothesis test: (2 points)
  2. Make a conclusion of hypothesis test in context: (3 points)
    Subject Before After
    1 201 196
    2 178 171
    3 169 170
    4 212 207
    5 180 177
    6 192 190
    7 158 159
    8 180 180
    9 170 164
    10 153 152
    11 183 179
    12 165 162
    13 201 199
    14 179 173
    15 236 231
    16 144 140

Solutions

Expert Solution

a) The average weight before physical exercise is mu1
The average weight after physical exercise is mu2

b) H0: The physical program will be considered not effective
H1: The physical program will be considered effective

c) Paired t - test is used since the samples are not independent

d) Normality assumption:

The distribution is follows normal distribution

e) From the given data

Test Statistic t = 5.0814

P-value = 0.000

df = 15

f) since p-value < alpha 0.05 so we reject H0

g) Thus we conclude that  the physical program will be considered effective


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