Question

Design an algorithm to prompt user to enter a number. Determine the number is odd or even with Case Logic.

Answer 1

Algorithm

step 1 : start

step 2 : Input the number from user , say num.

step 3: perform modulus operation of this number by 2 in switch case . ie switch( num % 2). (This will return only two case values either 0 or 1).

step 4: for case value 0 , print "the number is even " and then exit from program.

step 5 : for case value 1 , print "the number is odd " and then exit from program.

step 6 : stop

if you are willing to know its program , here it is , in c++

program

#include <iostream>

using namespace std;

int main()
{
int num;
cout<<"Enter a number:";
cin>>num;
switch(num%2)
{
case 0:cout<<num<<" is even number";
break;
case 1:cout<<num<<" is odd number";
break;

//default case is not required since this switch case only return either 0 or 1
}
}

output

Enter a number:5

5 is odd number

Enter a number:6

6 is even number

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