In: Math
Here comes BBA (Body-By-Agbegha) program again! A group of women of comparable age, weight and height was subjected to three weight loss treatments - BBA1, BBA2 and BBA3. The table below shows the weight loss for the women.
| 
 BBA1  | 
 BBA2  | 
 BBA3  | 
| 
 21  | 
 27  | 
 14  | 
| 
 11  | 
 34  | 
 32  | 
| 
 19  | 
 28  | 
 29  | 
| 
 21  | 
 31  | 
 30  | 
| 
 26  | 
 19  | 
 25  | 
| 
 26  | 
 30  | 
 11  | 
| 
 11  | 
 22  | 
 22  | 
| 
 13  | 
 38  | 
 19  | 
| 
 12  | 
 31  | 
 23  | 
Test to see whether there is any significant difference in the mean weight loss between the programs. Use a 5% level of significance.
State the null and alternative hypotheses.
Find the critical F value.
State a decision rule.
Find the value of the F Statistics.
Find the p-value.
State your decision.
Draw an appropriate conclusion using the context of the problem.
using excel data analusis tool for one way anova,we get
| Anova: Single Factor | ||||||
| SUMMARY | ||||||
| Groups | Count | Sum | Average | Variance | ||
| BBA1 | 9 | 160 | 17.778 | 38.194 | ||
| BBA2 | 9 | 260 | 28.889 | 33.611 | ||
| BBA3 | 9 | 205 | 22.778 | 51.444 | ||
| ANOVA | ||||||
| Source of Variation | SS | df | MS | F | P-value | F crit | 
| Between Groups | 557.4074 | 2 | 278.7037 | 6.7839 | 0.0046 | 3.4028 | 
| Within Groups | 986.0000 | 24 | 41.0833 | |||
| Total | 1543.4074 | 26 | 
------------------------
null hypothesis:all means are equal
or
null hypothesis:there is no significant difference in the mean weight loss between the programs
alternate hypothesis:not all means are equal
or
alternate hypotheis:there is a significant difference in the mean weight loss between the programs
critical F value = 3.4028
a decision rule
if F-stat>3.4028,then reject H0,otherwise not
---------------
F Statistics.=6.7839
--------------
p-value=0.0046
---------------
since,p-value<alpha=0.05,null hypothesis is rejected
----------------
conclusion:there is enough evidence that there is a significant difference in the mean weight loss between the programs