In: Math
Here comes BBA (Body-By-Agbegha) program again! A group of women of comparable age, weight and height was subjected to three weight loss treatments - BBA1, BBA2 and BBA3. The table below shows the weight loss for the women.
BBA1 |
BBA2 |
BBA3 |
21 |
27 |
14 |
11 |
34 |
32 |
19 |
28 |
29 |
21 |
31 |
30 |
26 |
19 |
25 |
26 |
30 |
11 |
11 |
22 |
22 |
13 |
38 |
19 |
12 |
31 |
23 |
Test to see whether there is any significant difference in the mean weight loss between the programs. Use a 5% level of significance.
State the null and alternative hypotheses.
Find the critical F value.
State a decision rule.
Find the value of the F Statistics.
Find the p-value.
State your decision.
Draw an appropriate conclusion using the context of the problem.
using excel data analusis tool for one way anova,we get
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
BBA1 | 9 | 160 | 17.778 | 38.194 | ||
BBA2 | 9 | 260 | 28.889 | 33.611 | ||
BBA3 | 9 | 205 | 22.778 | 51.444 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 557.4074 | 2 | 278.7037 | 6.7839 | 0.0046 | 3.4028 |
Within Groups | 986.0000 | 24 | 41.0833 | |||
Total | 1543.4074 | 26 |
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null hypothesis:all means are equal
or
null hypothesis:there is no significant difference in the mean weight loss between the programs
alternate hypothesis:not all means are equal
or
alternate hypotheis:there is a significant difference in the mean weight loss between the programs
critical F value = 3.4028
a decision rule
if F-stat>3.4028,then reject H0,otherwise not
---------------
F Statistics.=6.7839
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p-value=0.0046
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since,p-value<alpha=0.05,null hypothesis is rejected
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conclusion:there is enough evidence that there is a significant difference in the mean weight loss between the programs