Mean = 0.38 Standard deviation = 0.063 a. Since the sampling distribution is approximately normal, use...

Mean = 0.38

Standard deviation = 0.063

a. Since the sampling distribution is approximately normal, use the NORM.DIST function to determine the probability that a randomly selected sample of size n = 60 will have a sample proportion of females less than .2, i.e., 20%.

b. Suppose the company claims that they randomly selected from this population and the random sample contains 8 females out of 60. Draw a data distribution.

c. considering the last part, do you believe that the company truly randomly sampled from the population of all employees?

Expert Solution

a) probability(X<0.20) : 0.002137367

b) probability(X=8/60) = P(X=0.133) : 0.002410701

c) yes, I believe company truly sampled from the population of all employees.

I HOPE I WAS HELPFUL AND HAVE CLEARED YOUR DOUBTS.

THANKYOU

orchestra answered 2 years ago

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