In: Finance
Joe plans to deposit $200 at the end of each month into a bank account for a period of 2 years, after which he plans to deposit $300 at the end of each month into the same account for another 3 years. If the bank pays interest at the rate of 3.5%/year compounded monthly, how much will Joe have in his account by the end of 5 years? (Assume that no withdrawals are made during the 5-year period.)
Joe will have in his account by the end of 5 years $ 16,883.35
Step-1:Future value of monthly deposit of first 2 years | ||||||||
Future Value | = | Monthly deposit | * | Future value of annuity of 1 | * | Future value of 1 | ||
= | $ 200.00 | * | 24.8225808 | * | 1.110554 | |||
= | $ 5,513.36 | |||||||
Working: | ||||||||
Future value of annuity of 1 | = | (((1+i)^n)-1)/i | Where, | |||||
= | (((1+0.002917)^24)-1)/0.002917 | i | = | 3.5%/12 | = | 0.002917 | ||
= | 24.8225808 | n | = | 2*12 | = | 24 | ||
Future value of 1 | = | (1+i)^n | Where, | |||||
= | (1+0.002917)^36 | i | = | 3.5%/12 | = | 0.002917 | ||
= | 1.11055416 | n | = | 3*12 | = | 36 | ||
Step-2:Future value of monthly deposit of next 3 years | ||||||||
Future Value | = | Monthly deposit | * | Future value of annuity of 1 | ||||
= | $ 300.00 | * | 37.8999532 | |||||
= | $ 11,369.99 | |||||||
Working: | ||||||||
Future value of annuity of 1 | = | (((1+i)^n)-1)/i | Where, | |||||
= | (((1+0.002917)^36)-1)/0.002917 | i | = | 3.5%/12 | = | 0.002917 | ||
= | 37.8999532 | n | = | 3*12 | = | 36 | ||
Step-3:Future value of deposit at the end of 5 years | ||||||||
Future value of deposit | = | $ 5,513.36 | + | $ 11,369.99 | ||||
= | $ 16,883.35 |