Question

In: Statistics and Probability

Super Sneaker Company is evaluating two different materials, A and B, to be used to construct...

Super Sneaker Company is evaluating two different materials, A and B, to be used to construct the soles of their new active shoe targeted to city high school students in Canada. While material B costs less than material A, the company suspects that mean wear for material B is greater than mean wear for material A. Two study designs were initially developed to test this suspicion. In both designs, Halifax was chosen as a representative city of the targeted market. In Study Design 1, 8 high school students were drawn at random from the Halifax School District database. After obtaining their shoe sizes, the company manufactured 8 pairs of shoes, each pair with one shoe having a sole constructed from material A and the other shoe, a sole constructed from material B.

After 3 months, the amount of wear in each shoe was recorded in standardized units as follows:

1 2 3 4 5 6 7 8
A 17.23 13.09 11.13 15.02 12.01 11.68 13.62 13.45
B 14.73 15.17 13.73 13.08 15.51 14.09 12.70

14.57

What is the 99% confidence interval for the difference in wear between material B and material A (use B-A)? Use software to get a more precise critical value, but confirm it's roughtly the same value you get from the table. Use at least 5 digits to the right of the decimal. Lower bound:  Upper bound:

Alternative hypothesis was: uA-uB < 0

Solutions

Expert Solution

from software critical value of t= 3.49948 which is approximately the same from table which is 3.499

for 99% CI; and 7 degree of freedom, value of t= 3.49948
therefore confidence interval=sample mean -/+ t*std error
margin of errror          =t*std error=             2.81433
lower confidence limit                     = -2.02058
upper confidence limit                    = 3.60808

lower bound =-2.02058

upper bound =3.60808


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