In: Statistics and Probability
Super Sneaker Company is evaluating two different materials, A and B, to be used to construct the soles of their new active shoe targeted to city high school students in Canada. While material B costs less than material A, the company suspects that mean wear for material B is greater than mean wear for material A. Two study designs were initially developed to test this suspicion. In both designs, Halifax was chosen as a representative city of the targeted market. In Study Design 1, 8 high school students were drawn at random from the Halifax School District database. After obtaining their shoe sizes, the company manufactured 8 pairs of shoes, each pair with one shoe having a sole constructed from material A and the other shoe, a sole constructed from material B.
After 3 months, the amount of wear in each shoe was recorded in standardized units as follows:
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | |
A | 17.23 | 13.09 | 11.13 | 15.02 | 12.01 | 11.68 | 13.62 | 13.45 |
B | 14.73 | 15.17 | 13.73 | 13.08 | 15.51 | 14.09 | 12.70 |
14.57 |
What is the 99% confidence interval for the difference in wear between material B and material A (use B-A)? Use software to get a more precise critical value, but confirm it's roughtly the same value you get from the table. Use at least 5 digits to the right of the decimal. Lower bound: Upper bound:
Alternative hypothesis was: uA-uB < 0
from software critical value of t= 3.49948 which is approximately the same from table which is 3.499
for 99% CI; and 7 degree of freedom, value of t= | 3.49948 | ||
therefore confidence interval=sample mean -/+ t*std error | |||
margin of errror =t*std error= | 2.81433 | ||
lower confidence limit = | -2.02058 | ||
upper confidence limit = | 3.60808 |
lower bound =-2.02058
upper bound =3.60808