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A mixture of benzene and toluene boils at 95°C under a pressure of 101.3kPa. Calculate the...
A mixture of benzene and toluene boils at 95°C under a
pressure of 101.3kPa. Calculate
the composition of the boiling liquid assuming the mixture obeys
Raoult’s law. At 95°C,
the vapour pressure of benzene is 155.56 kPa and that of toluene is
63.98 kPa.
Solutions
Amanda K answered 2 months agoRelated Solutions
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A mixture of benzene and toluene is in a tank whose pressure is
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(Document...
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1. K-constant=1.48
2.alpha constant=2.41
At 87°C the vapor pressure of benzene is 931 torr and that of toluene is 290...
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The vapor pressures of benzene and toluene at 95◦C are, respectively, 155.7 kPa and 63.3 kPa....
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respectively, 155.7 kPa and 63.3 kPa. A gaseous mixture consisting
of 50 moles of benzene and 50 moles of toluene was cooled to 95◦C.
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condensed. If the total pressure above the condensate was 101.3
kPa, calculate:
(a) the mole fraction of benzene in the condensate
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Data for benzene and toluene are given below. Calculate the vapor pressure over a solution made...
Data for benzene and toluene are given below. Calculate the
vapor pressure over a solution made by mixing 20.0 grams of benzene
with 80.0 grams of toluene when the temperature is 40.0ºC.
Compound Molar
Mass
Vapor Pressure at 40.0ºC
Benzene
78.11
g/mol
183 mm Hg
Toluene
92.14
g/mol
59 mm Hg
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