L ={x^a y^b z^c | c=a+b} a) Prove that L is not regular. b)Prove by giving...

L ={x^a y^b z^c | c=a+b} a) Prove that L is not regular. b)Prove by giving a context-free grammar that the L is context free. c)Give a regular expression of the complement L'.

Expert Solution

hello

I have used Pumping lemma to prove that the given language is not regular
If NPDA (nondeterministic pushdown automaton) exist for a given language, then the give is Context-free language, and its grammar is a context-free grammar
The complement of Context-free language is not Regular, and Regular expression only exist For Regular Languages in Finite automata

thank you ,

venereology answered 7 months ago

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L ={x^a y^b z^c | c=a+b} a) Prove that L is not regular. b)Prove by giving...

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