Question

Here we consider the sleep habits of med students versus non-med students. The study consists of the hours of sleep per day obtained from 27 med students and 30 non-med students. The summarized data is given in the table. Here, x¯x¯ is the mean hours of sleep per day from each sample. The degrees of freedom (d.f.) that you must use in your calculations are given below.

Student Type	nn	x¯x¯	s2s2	ss
Med (x1x1)	27	5.7	0.6561	0.81
Non-Med (x2x2)	30	6.2	1.7161	1.31
degrees of freedom: d.f. = 49

Test the claim that the mean hours of sleep for med and non-med students is different. Use a 0.05 significance level.

(a) Find the test statistic.

(b) Find the P-value.

(c) Is there sufficient data to support the claim?
Yes
No

Test the claim that, on average, med students get less sleep than non-med students. Use a 0.05 significance level.

(d) Is there sufficient data to support the claim?
Yes
No

Answer 1

n1 = 27

= 5.7

s1 = 0.81

n2 = 30

= 6.2

s2 = 1.31

Claim: The mean hours of sleep for med and non-med students is different.

The null and alternative hypothesis is:

a)

Test statistic is

b)

Degrees of freedom = 49

P-value = 2*P(T < -1.75) = 2*0.0431 = 0.0861

c)

P-value > 0.05 we fail to reject null hypothesis.

No

Test the claim that, on average, med students get less sleep than non-med students. Use a 0.05 significance level.

The null and alternative hypothesis is:

Test statistic is

Degrees of freedom = 49

P-value = P(T < -1.75) = 0.0431

d)

P-value < 0.05 we reject null hypothesis.

Yes