Question

(Programming Language: Python)

Complete the function remove number such that given a list of integers and an integer n, the function removes every instance of
n from the list. Remember that this function needs to modify the list, not return a new list.

# DO NOT ADD ANY OTHER IMPORTS from typing import List

def remove_number(lst: List[int], number: int) -> None:

"""

Remove every instance of number in lst. Do this *in-place*, i.e. *modify* the list. Do NOT return a new list.

>>> lst = [1, 2, 3]

>>> remove_number(lst, 3)

>>> lst

[1, 2]

"""

pass

Answer 1

Please find the code below with the comments at every line of the code and also screenshot of the execution.

#this program will return the list after removing the element that has been passed to remove_number(lst, element)

#defining the function remove_number
def remove_number(lst, element):
  #iterating through the loop to remove all the occurences of element in the passed list
  for iter in range(len(lst) - 1, -1, -1):
    #checking the condition that if it matches the given given element
    if lst[iter] == element:
      #deleting the element from the list
        del lst[iter]
  #returning the same list(not the new list)
  return lst

#initialinzing the list
lst = [1,2,3,3,3,4,4,2,5,3,2,1,0]

#calling the remove_number method to remove 3 from the list
remove_number(lst,3)

#priniting the list lst
print(lst)

Screenshot of the execution:

Another way of execution :

you can execute by commenting return also to check whether its removing in the same list or new list:
please find the screenshot below for the same after commenting return from line 12