Consider a router that has the following Routing Table contents: Destination Subnet Outgoing Interface Next Hop...

Consider a router that has the following Routing Table contents:

*Destination Subnet*	*Outgoing Interface*	*Next Hop*
50.62.8.0/24	Fa0/0	118.2.77.4
24.19.0.0/16	Fa0/1	59.16.1.1
0.0.0.0/0	Fa0/2	18.12.52.43

0.0.0.0/0 is the default route. When a packet arrives, the router checks the destination IP address of the packet to see in which subnet it falls. If the destination IP address does not fall within any of the specified subnets, then the default route is used as a last resort. The packet is consequently forwarded out Fa0/2.

A packet with destination IP address 50.62.8.154 arrives to this router. Out what interface will this packet be sent?
A packet with destination IP address 50.62.25.2 arrives to this router. Out what interface will this packet be sent?
A packet with destination IP address 50.61.9.93 arrives to this router. Out what interface will this packet be sent?
A packet with destination IP address 24.19.104.3 arrives to this router. Out what interface will this packet be sent?
A packet with destination IP address 24.18.8.1 arrives to this router. Out what interface will this packet be sent?

Expert Solution

Answer A
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packet will forward to interface Fa0/0 , because /24 range is 0-254 and here last octet is 154 which fall between this range.

Answer B
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packet will forward to interface Fa0/2 because its defaut route and no .25 subnet is found in the table.

Answer C
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packet will forward to interface Fa0/2 because its defaut route and no .9 subnet is found in the table.

Answer D
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packet will forward to interface Fa0/1 , because /16 range is 0-65534 and 24.19.0.0 to 24.19.255.255 so it fall in between this range.

Answer E
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packet will forward to interface Fa0/2 , because route .19 is there but we have .19 route.

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venereology answered 7 months ago

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