In: Physics
point charges are q1=8 μC, q2=-7 μC Find
the electric field due to these charges at the origin: (o)
(q1)<------10cm------o----------10cm---------->(q2)
(q1)A<---------10cm------O----------10cm---------->B(q2)
8 μC------------------------>--------------------------->-7 μC
E1 E2
Distance between the two charges , AB=20 cm
Let net elctric field at O is Eo
Magnitude of electric field at point O caused by q1=8 μC charge,
where, ε0=Permittivity of free space and
Magnitude of electric field at point O cause by q2= - 7 μC charge,
in diagram you can see that direction of electric field intensities are in the same direction
Hence, electric field at the midpoint O of the line AB joining the charges is 13.5 × 10⁶ N/C along OB