In: Accounting
There are 20 payment periods, between periods 1 and 12 the interest of the loan is 750, and between periods 13 and 16 the interest payment is 600. So the principle for the sinking fund from periods 1 to 12 is 650, and from periods 13 to 16 is 800. So I found the future value of the sinking fund in Table 1 Below, which equals 13729.52, and since the loan value remains the same, I take the future value of the sinking fund and subtract it from 15000 (the loan amount) to arrive at the value the sinking fund is short, which is 1270.48.
Table 1
D | E | F | |||
Loan repayment | Years | Interest(15000*i/100) | Principal | Sinking fund value calculation | Sinking fund value |
1400 | 1 | 750 | 650 | =F2*1.03^(16-D2) | 1012.679 |
1400 | 2 | 750 | 650 | =F3*1.03^(16-D3) | 983.1833 |
1400 | 3 | 750 | 650 | =F4*1.03^(16-D4) | 954.5469 |
1400 | 4 | 750 | 650 | =F5*1.03^(16-D5) | 926.7446 |
1400 | 5 | 750 | 650 | =F6*1.03^(16-D6) | 899.752 |
1400 | 6 | 750 | 650 | =F7*1.03^(16-D7) | 873.5456 |
1400 | 7 | 750 | 650 | =F8*1.03^(16-D8) | 848.1026 |
1400 | 8 | 750 | 650 | =F9*1.03^(16-D9) | 823.4006 |
1400 | 9 | 750 | 650 | =F10*1.03^(16-D10) | 799.418 |
1400 | 10 | 750 | 650 | =F11*1.03^(16-D11) | 776.134 |
1400 | 11 | 750 | 650 | =F12*1.03^(16-D12) | 753.5281 |
1400 | 12 | 750 | 650 | =F13*1.03^(16-D13) | 731.5807 |
1400 | 13 | 600 | 800 | =F14*1.03^(16-D14) | 874.1816 |
1400 | 14 | 600 | 800 | =F15*1.03^(16-D15) | 848.72 |
1400 | 15 | 600 | 800 | =F16*1.03^(16-D16) | 824 |
1400 | 16 | 600 | 800 | =F17*1.03^(16-D17) | 800 |
13729.52 | |||||
Principal | 15000 | ||||
Shortage | 1270.483 |
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