In: Statistics and Probability
A campus student club distributed material about membership to new students attending an orientation meeting. Of those receiving this material, 35% were men and 65% were women. Subsequently, it was found that 8% of the men and 11% of the women who received this material joined the club. Complete parts a and b below.
a. Find the probability that a randomly chosen new student who receives the membership material will join the club. nothing (Round to four decimal places as needed.)
b. Find the probability that a randomly chosen new student who joins the club after receiving the membership material is a woman. nothing (Round to four decimal places as needed.)
(a)
From the given data,the following Table is calculated:
Men | Women | Total | |
Joined the club | 0.35 X 0.08 = 0.028 | 0.65 X 0.11 = 0.0715 | 0.0995 |
Did not join the club | 0.35 - 0.028 =0.322 | 0.5785 | 0.9005 |
Total | 0.35 | 0.65 | 1.00 |
So,
the probability that a randomly chosen new student who receives the membership material will join the club. = 0.0995
So,
Answer is:
0.0995
(b)
P(Woman/ Joined the club) = P(Woman AND Joined the club)/ P(Joined the club)
= 0.0715/ 0.0995
= 0.7186
So,
Answer is:
0.7186