Question

In: Other

why can you write U (Internal energy) as a function of two thermodynamic properties and not...

why can you write U (Internal energy) as a function of two thermodynamic properties and not all three (P, V, T)? Why is the state fully specified by specifying only two properties? what is the internal energy state equation?

Solutions

Expert Solution

This is based on gibss phase rule.

for example, consider water in a bowl single component . its phase is a liquid phase (single phase).

according to the phase rule number of independent variables required to define a system is given by Gibbs phase rule.

formula F = C - P + 2

F = number of independent variables required to specify any system.

C = number of components

P = number of phases

2 represents any two variables which can be varied (temperature, pressure) or  (temperature, composition) or  (composition, pressure).

for water in bowl F = 1-1+2 = 2

2 independent variables required .

it can be (temperature, pressure) or  (temperature, composition) or  (composition, pressure).

SO now internal energy is a function of (temperature, pressure) or  (temperature, composition) or  (composition, pressure).

We can write U = U(T, P) or U=U(T, V)

If F=3 We require three variables to define system it can be (temperature, pressure, volume) or  (temperature, composition, pressure)

We can write U = U(T, P, V) or U=U(T, V, X)

internal energy state equation is given by the first law of thermodynamics

dQ = dU+dW

TdS = dU + pdV

dU = Tds - PdV


Related Solutions

derive the expressions for the thermodynamic properties Helmholtz free energy, entropy, pressure, chemical potential and internal...
derive the expressions for the thermodynamic properties Helmholtz free energy, entropy, pressure, chemical potential and internal energy for the canonical ensemble as a function of the partition function
Based on the thermodynamic properties provided for water, determine the amount of energy needed for 269...
Based on the thermodynamic properties provided for water, determine the amount of energy needed for 269 g of water to go from 85.5 °C to 161 °C. Property Value Units Melting point 0.0 °C Boiling point 100.0 °C ΔHfusΔHfus 6.01 kJ/mol ΔHvapΔHvap 40.67 kJ/mol cp (s) 37.1 J/mol·°C cp (l) 75.3 J/mol·°C cp (g) 33.6 J/mol·°C
Based on the thermodynamic properties provided for water, determine the energy change when the temperature of...
Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 1.45 kg of water decreased from 109 °C to 23.0 °C.
Based on the thermodynamic properties provided for water, determine the energy change when the temperature of...
Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 0.750 kg of water decreased from 117 °C to 38.5 °C. Property Value Units Melting point 0 °C Boiling point 100.0 °C ΔHfus 6.01 kJ/mol ΔHvap 40.67 kJ/mol cp (s) 37.1 J/mol · °C cp (l) 75.3 J/mol · °C cp (g) 33.6 J/mol · °C
Based on the thermodynamic properties provided for water, determine the energy change when the temperature of...
Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 0.750 kg of water decreased from 111 °C to 51.0 °C. Melting point 0 °C Boiling point 100.0 °C ΔHfus 6.01 kJ/mol ΔHvap 40.67 kJ/mol cp (s) 37.1 J/mol · °C cp (l) 75.3 J/mol · °C cp (g) 33.6 J/mol · °C
The thermodynamic properties of foods can be discussed in terms of the enthalpy of combustion per...
The thermodynamic properties of foods can be discussed in terms of the enthalpy of combustion per gram of food. Do you get more energy from the metabolism of one gram of sugar or one gram of fat? Answer this question quantitatively and with as much thermodynamic detail as possible. Use two of the following three methods to quantify your answer: (A) arithmetic method, (B) calorimetry, and/or (C) computational.
The differential for the Internal energy, U, at constant composition is ?U = −P?V + T?S...
The differential for the Internal energy, U, at constant composition is ?U = −P?V + T?S (a) What are the natural independent variables of U? [2] (b) Derive an expression for the change in internal energy at constant Volume starting with the above differential for the internal function, U, at constant composition. [3] (c) Using the criterion for exact differentials, write the Maxwell relation that is derived from this equation. [2] (d) Based on your answer in part (a), write...
Properties/Characteristics You are to write down as many properties and/or characteristics of materials as you can...
Properties/Characteristics You are to write down as many properties and/or characteristics of materials as you can think of (not just for one material, but any and all materials). Try to get one that starts with each letter of the alphabet…!     General principles in Construction for landscape architecture A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
In first law of thermodynamics, internal energy U is defined, and it is used to predict...
In first law of thermodynamics, internal energy U is defined, and it is used to predict the magnitude of heat and work conversion. However, we actually use enthalpy(H) more than U. What is the difference between U and H? And why a new thermodynamic function H is needed, even though U was first defined which is suitable for the first law?
Internal energy change is the sum of heat and work. Explain why the internal energy change...
Internal energy change is the sum of heat and work. Explain why the internal energy change of the reaction between hydrochloric acid and sodium hydroxide can be determined with only a small error by determining the heat of the reaction. Explain why the error woul d be larger if sodium carbonate is used as the base in place of the sodium hydroxide.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT